Chapter 3 problems: Difference between revisions

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*<math>I_B</math> can be read from the load line graph. We can then use this information to find the voltage over <math>V_B</math>.
*<math>I_B</math> can be read from the load line graph. We can then use this information to find the voltage over <math>V_B</math>.
'''Part C'''
'''Part C'''
*Using KCL: <math>-V_C/500+I_C+V_C/500=0</math>
*Thevenin Equivalent: <math>R_{th}=500</math> and <math>V_{oc}=</math>
*I believe there is a problem with my equation.


===3.17===
===3.17===

Revision as of 13:53, 2 March 2010

3.9

Part A

  • Using KVL:
  • Thus the two points for the load line are and
  • Overlay the above two points with the diode characteristics to find the answer.

Part B

  • Thevenin Equivalent: and
  • Using KVL: , thus and for the load line.
  • can be read from the load line graph. We can then use this information to find the voltage over .

Part C

  • Thevenin Equivalent: and

3.17

Part A

  • Guessing D1 is on, D2 and D3 are off. Looking at the voltage drops, this is very unlikely.
  • Guessing D1 off, D2 on, D3 off. and .
  • Checking for positive current through presumed on diodes and negative voltage across the presumed off diodes.
  • D1 and D2 fail. D3 passes.
  • Guessing D1 and D2 on, D3 off.
  • and . D1, D2, D3 pass.

Check each guess please. More importantly, check the wrong assumptions.

Part B Need help on this one.

  • , : D1, D4 on. D2, D3 off.
  • , : D1, D4 on. D2, D3 off.
  • , : D2, D3 on. D1, D4 off.
  • , : D2, D3 on. D1, D4 off.

V=0. D1, D4 on. Can you really sink current into a voltage source? I don't see how you will ever have negative voltage across the diodes.

3.32

  • How does this circuit work?

3.33

P3.33.PNG

3.37