Chapter 4 problems: Difference between revisions

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*<math>A_v \cong (19-12)/.4=12.5</math>


===4.34===
===4.34===

Latest revision as of 12:36, 5 March 2010

4.20

  • We want to establish a DC operating point for the BJT. Writing a loop equation gives us -VBB-Vin(t)+iBRB+vBE=0. To form a load line, we will let vin(t)=0 & iB=0. Thus vBE=VBB+vin(t) and iB(t)=(VBB+vin(t))/RB
  • for the minimum, Q-point and maximum values.
V V uA
-.2 .45 2
0 .58 5
.2 .62 10
  • Writing a loop equation for the output: .
V V mA
-.2 19 .8
0 16 2
.2 12 4

4.34

4.45

4.64