Chapter 1 - Revision history

Fonggr: /* Inductor */

2010-03-11T21:50:23Z

Inductor

← Older revision		Revision as of 14:50, 11 March 2010
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	==Inductor==		==Inductor==
	:<math>v(t) = L \frac{di(t)}{dt}</math>		:<math>v(t) = L \frac{di(t)}{dt}</math>
	:<math>i(t) = \frac{1}{L} \int^t_0 v(x)dx + i(0)</math>		:<math>i(t) = \frac{1}{L} \int^t_{t_0} v(\tau)d\tau + i({t_0})</math>

	==Reviewers==		==Reviewers==

Fonggr: /* Inductor */

2010-03-11T21:44:24Z

Inductor

← Older revision		Revision as of 14:44, 11 March 2010
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	==Inductor==		==Inductor==
	:<math>v(t) = L \frac{di(t)}{dt}</math>		:<math>v(t) = L \frac{di(t)}{dt}</math>
			:<math>i(t) = \frac{1}{L} \int^t_0 v(x)dx + i(0)</math>

	==Reviewers==		==Reviewers==

Fonggr at 20:04, 11 March 2010

2010-03-11T20:04:50Z

← Older revision		Revision as of 13:04, 11 March 2010
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	=Amplifier Models=		==Amplifier Models==
	*These are purely models, and cannot be replicated in a real world environment. They are meant to explain.		*These are purely models, and cannot be replicated in a real world environment. They are meant to explain.
	*Trans stands for transfer (from voltage to current or visa versa).		*Trans stands for transfer (from voltage to current or visa versa).
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	\|}		\|}

	=Differential Amplifiers=		==Differential Amplifiers==
	[[Image:Differential Amplifier.PNG\|thumb\|300px\| Differential Amplifier inputs]]		[[Image:Differential Amplifier.PNG\|thumb\|300px\| Differential Amplifier inputs]]
	*Differential amplifiers take two (or more) input sources and produce an output voltage proportional to the difference between the input voltages.		*Differential amplifiers take two (or more) input sources and produce an output voltage proportional to the difference between the input voltages.
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	**In decibels, <math> CMRR = 20 \log \frac{\| A_d \|}{\| A_{cm}\|}</math>		**In decibels, <math> CMRR = 20 \log \frac{\| A_d \|}{\| A_{cm}\|}</math>

	=Definitions=		==Definitions==
	*Input Resistance: <math>R_i</math> of an amplifier is the equivalent resistance seen when looking into the input terminals.		*Input Resistance: <math>R_i</math> of an amplifier is the equivalent resistance seen when looking into the input terminals.
	*Output Resistance: <math>R_o</math> is the Thevenin resistance seen when looking back into the output terminals of an amplifier.		*Output Resistance: <math>R_o</math> is the Thevenin resistance seen when looking back into the output terminals of an amplifier.
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	*Short-circuit current gain: the current gain with the output terminals of the amplifier short circuited.		*Short-circuit current gain: the current gain with the output terminals of the amplifier short circuited.

	=Reviewers=		==Capacitor==
			:<math>v(t)= \frac{q(t)}{C} = \frac{1}{C}\int_{t_0}^t i(\tau) \mathrm{d}\tau+v(t_0)</math>
			:<math>i(t)= \frac{\mathrm{d}q(t)}{\mathrm{d}t}=C\frac{\mathrm{d}v(t)}{\mathrm{d}t}</math>
			==Inductor==
			:<math>v(t) = L \frac{di(t)}{dt}</math>

			==Reviewers==
	*[[Lau, Chris \| Christopher Garrison Lau I]]		*[[Lau, Chris \| Christopher Garrison Lau I]]
	*[[Vier, Michael \| Michael Vier]]		*[[Vier, Michael \| Michael Vier]]

	=Readers=		==Readers==

	*[[Lau, Chris \| Christopher Garrison Lau I]]		*[[Lau, Chris \| Christopher Garrison Lau I]]

Cdxskier at 02:52, 18 January 2010

2010-01-18T02:52:11Z

← Older revision		Revision as of 19:52, 17 January 2010
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	*[[Lau, Chris \| Christopher Garrison Lau I]]		*[[Lau, Chris \| Christopher Garrison Lau I]]
	*[[Vier, Michael \| Michael Vier]]		*[[Vier, Michael \| Michael Vier]]

			=Readers=

			*[[Lau, Chris \| Christopher Garrison Lau I]]

Fonggr: /* Differential Amplifiers */

2010-01-12T20:06:56Z

Differential Amplifiers

← Older revision		Revision as of 13:06, 12 January 2010
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	=Differential Amplifiers=		=Differential Amplifiers=
	[[Image:Differential Amplifier.PNG\|thumb\|300px\| Differential Amplifier inputs]]		[[Image:Differential Amplifier.PNG\|thumb\|300px\| Differential Amplifier inputs]]
	*Differential amplifiers take two (or more) input sources ~~that~~ produce an output voltage proportional to the difference between the input voltages.		*Differential amplifiers take two (or more) input sources and produce an output voltage proportional to the difference between the input voltages.
	*Instead of expressing the input voltages in terms of <math>v_{1}\,</math> and <math>v_{i}\,</math>, we can express them in terms of the differential and common-mode input.		*Instead of expressing the input voltages in terms of <math>v_{1}\,</math> and <math>v_{i}\,</math>, we can express them in terms of the differential and common-mode input.
	**Differential input signal is the difference between the input voltages. <math>v_{d}=v_{1}-v_{2}\,</math>		**Differential input signal is the difference between the input voltages. <math>v_{d}=v_{1}-v_{2}\,</math>

Fonggr: /* Differential Amplifiers */

2010-01-12T20:06:09Z

Differential Amplifiers

← Older revision		Revision as of 13:06, 12 January 2010
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	*<math>v_o=A_d v_{d} + A_{cm} v_{cm}\,</math>, where <math>A_d\,</math> is the differential gain and <math>A_{cm}\,</math> is the common mode gain.		*<math>v_o=A_d v_{d} + A_{cm} v_{cm}\,</math>, where <math>A_d\,</math> is the differential gain and <math>A_{cm}\,</math> is the common mode gain.
	*The common-mode rejection ratio (CMRR) is the ratio of the magnitude of the differential gain to the magnitude of the common-mode gain.		*The common-mode rejection ratio (CMRR) is the ratio of the magnitude of the differential gain to the magnitude of the common-mode gain.
	**In decibels, <math> CMRR = 20 \log \frac{\| A_d \|}{\| ~~A_cm~~\|}</math>		**In decibels, <math> CMRR = 20 \log \frac{\| A_d \|}{\| A_{cm}\|}</math>

	=Definitions=		=Definitions=

Fonggr: /* Reviewers */

2010-01-12T20:06:01Z

Reviewers

← Older revision		Revision as of 13:06, 12 January 2010
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	=Reviewers=		=Reviewers=
	*[[Lau, Chris \| Christopher Garrison Lau I]]		*[[Lau, Chris \| Christopher Garrison Lau I]]
	*[[Vier, Michael \| Michael Vier]] ~~-- Make sure you subscript the 'm' in the CMRR formula.~~		*[[Vier, Michael \| Michael Vier]]

Michaelvier at 19:27, 12 January 2010

2010-01-12T19:27:32Z

← Older revision		Revision as of 12:27, 12 January 2010
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	=Reviewers=		=Reviewers=
	[[Lau, Chris \| Christopher Garrison Lau I]]		*[[Lau, Chris \| Christopher Garrison Lau I]]
	[[Vier, Michael \| Michael Vier]] -- Make sure you subscript the 'm' in the CMRR formula.		*[[Vier, Michael \| Michael Vier]] -- Make sure you subscript the 'm' in the CMRR formula.

Michaelvier at 19:27, 12 January 2010

2010-01-12T19:27:05Z

← Older revision		Revision as of 12:27, 12 January 2010
Line 67:		Line 67:
	=Reviewers=		=Reviewers=
	[[Lau, Chris \| Christopher Garrison Lau I]]		[[Lau, Chris \| Christopher Garrison Lau I]]
			[[Vier, Michael \| Michael Vier]] -- Make sure you subscript the 'm' in the CMRR formula.

Fonggr: /* Differential Amplifiers */

2010-01-12T06:41:27Z

Differential Amplifiers

← Older revision		Revision as of 23:41, 11 January 2010
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	[[Image:Differential Amplifier.PNG\|thumb\|300px\| Differential Amplifier inputs]]		[[Image:Differential Amplifier.PNG\|thumb\|300px\| Differential Amplifier inputs]]
	*Differential amplifiers take two (or more) input sources that produce an output voltage proportional to the difference between the input voltages.		*Differential amplifiers take two (or more) input sources that produce an output voltage proportional to the difference between the input voltages.
	*Instead of expressing the input voltages in terms of <math>v_{1}\,</math> and <math>v_{i}\,</math>, we can express them in terms of the differential and common-mode input. ~~How?~~		*Instead of expressing the input voltages in terms of <math>v_{1}\,</math> and <math>v_{i}\,</math>, we can express them in terms of the differential and common-mode input.
	**Differential input signal is the difference between the input voltages. <math>v_{d}=v_{1}-v_{2}\,</math>		**Differential input signal is the difference between the input voltages. <math>v_{d}=v_{1}-v_{2}\,</math>
	**Common-mode input signal is the average of the input voltages. <math>v_{cm}=\frac{1}{2}(v_{1}+v_{2})</math>		**Common-mode input signal is the average of the input voltages. <math>v_{cm}=\frac{1}{2}(v_{1}+v_{2})</math>