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	<title>Colby&#039;s Asgn - Revision history</title>
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	<updated>2026-06-10T00:27:33Z</updated>
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		<title>Colby.fullerton: Created page with &#039;Find the Thevenin equivalent impedance seen looking into the terminals of the following circuit: center  To find the Thevenin equivalent…&#039;</title>
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		<updated>2010-11-08T00:07:40Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;#039;Find the Thevenin equivalent impedance seen looking into the terminals of the following circuit: &lt;a href=&quot;/class-wiki/index.php/File:Lna_hw8_diagram1.jpg&quot; title=&quot;File:Lna hw8 diagram1.jpg&quot;&gt;thumb|400px|center&lt;/a&gt;  To find the Thevenin equivalent…&amp;#039;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;Find the Thevenin equivalent impedance seen looking into the terminals of the following circuit:&lt;br /&gt;
[[File:Lna hw8 diagram1.jpg|thumb|400px|center]]&lt;br /&gt;
&lt;br /&gt;
To find the Thevenin equivalent impedance I will need to take the Laplace transform of each branch of the circuit and add them in series.&lt;br /&gt;
&lt;br /&gt;
The Laplace transform of a resistor is&lt;br /&gt;
&amp;lt;math&amp;gt;\mathcal{L}\{resistor\} = R&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The Laplace transform of an inductor is&lt;br /&gt;
&amp;lt;math&amp;gt;\mathcal{L}\{inductor\} = sL&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The Laplace transform of a capacitor is&lt;br /&gt;
&amp;lt;math&amp;gt;\mathcal{L}\{\mbox{capacitor}\} = \frac{1}{sC}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Taking the Laplace transform of the original circuit gives the following.&lt;br /&gt;
[[File:Lna hw8 diagram2.jpg|thumb|400px|center]]&lt;br /&gt;
&lt;br /&gt;
The Thevenin equivalent impedance of this circuit is given by the equation&lt;br /&gt;
:&amp;lt;math&amp;gt;Z = \frac{1}{\frac{1}{R1+\frac{1}{sC}}+\frac{1}{R2+sL}} \Omega&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Substituting the values for R1, R2, C and L into the equation gives&lt;br /&gt;
:&amp;lt;math&amp;gt;Z = \frac{1}{\frac{1}{50+\frac{1}{.002s}}+\frac{1}{100+.5s}} \Omega = \frac{1}{\frac{s}{50(s+10)}+.5(s+200)} \Omega = \frac{2(s+10)}{s^2+210.04s+2000} \Omega&amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Colby.fullerton</name></author>
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