Key Facts from Reading - Revision history

Cdxskier: /* Differential Amplifiers */

2010-01-28T21:18:46Z

Differential Amplifiers

← Older revision		Revision as of 14:18, 28 January 2010
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	*The output of an ideal differential amplifier is given by <math>\ v_o=A_d v_{id} </math>.		*The output of an ideal differential amplifier is given by <math>\ v_o=A_d v_{id} </math>.
	*The common-mode input signal is given by the following: <math>v_{icm}=\frac{1}{2}(v_{i1}+v_{i2})</math>.		*The common-mode input signal is given by the following: <math>v_{icm}=\frac{1}{2}(v_{i1}+v_{i2})</math>.
	*A real differential amplifier's output is given by <math>\ v_o=A_d v_{id} </math>		*A real differential amplifier's output is given by <math>\ v_o=A_d v_{id}+A_{cm} v_{icm} </math>, where <math>A_{cm}</math> is the common-mode signal gain.

	==References==		==References==

Cdxskier: /* Differential Amplifiers */

2010-01-28T21:15:34Z

Differential Amplifiers

← Older revision		Revision as of 14:15, 28 January 2010
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	==Differential Amplifiers==		==Differential Amplifiers==
	*Differential Amplifiers have two inputs. The terminal marked with a "+" is the noninverting input, and the terminal marked with a "-" is the inverting input.		*Differential Amplifiers have two inputs. The terminal marked with a "+" is the noninverting input, and the terminal marked with a "-" is the inverting input.
			*The differential input signal is given by <math>\ v_{id}=v_{i1}-v_{i2} </math>
			*The output of an ideal differential amplifier is given by <math>\ v_o=A_d v_{id} </math>.
			*The common-mode input signal is given by the following: <math>v_{icm}=\frac{1}{2}(v_{i1}+v_{i2})</math>.
			*A real differential amplifier's output is given by <math>\ v_o=A_d v_{id} </math>

	==References==		==References==

Cdxskier at 19:34, 26 January 2010

2010-01-26T19:34:03Z

← Older revision		Revision as of 12:34, 26 January 2010
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	*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.		*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.
	*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.		*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.

			==Differential Amplifiers==
			*Differential Amplifiers have two inputs. The terminal marked with a "+" is the noninverting input, and the terminal marked with a "-" is the inverting input.

	==References==		==References==

Cdxskier: /* Decibel Conversion */

2010-01-26T18:51:13Z

Decibel Conversion

← Older revision		Revision as of 11:51, 26 January 2010
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	<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>		<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>
	*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.		*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.
	**For example, <math>\ 23 dbV = 14.12 V</math>
	*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.		*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.

Cdxskier: /* Decibel Conversion */

2010-01-26T18:50:37Z

Decibel Conversion

← Older revision		Revision as of 11:50, 26 January 2010
Line 24:		Line 24:
	<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>		<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>
	*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.		*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.
	**For example, <math>/ 23 dbV = 14.12 V</math>		**For example, <math>\ 23 dbV = 14.12 V</math>
	*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.		*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.

Cdxskier: /* Decibel Conversion */

2010-01-26T18:50:19Z

Decibel Conversion

← Older revision		Revision as of 11:50, 26 January 2010
Line 24:		Line 24:
	<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>		<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>
	*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.		*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.
			**For example, <math>/ 23 dbV = 14.12 V</math>
	*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.		*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.

Cdxskier: /* Decibel Conversion */

2010-01-26T18:46:37Z

Decibel Conversion

← Older revision		Revision as of 11:46, 26 January 2010
Line 24:		Line 24:
	<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>		<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>
	*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.		*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.
			*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.

	==References==		==References==

Cdxskier: /* Decibel Conversion */

2010-01-26T00:43:42Z

Decibel Conversion

← Older revision		Revision as of 17:43, 25 January 2010
Line 23:		Line 23:

	<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>		<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>
	*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>/ A_v</math> is the voltage gain and <math>/ A_{v dB}</math> is the voltage gain is decibels.		*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.

	==References==		==References==

Cdxskier: /* Decibel Conversion */

2010-01-26T00:43:26Z

Decibel Conversion

← Older revision		Revision as of 17:43, 25 January 2010
Line 23:		Line 23:

	<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>		<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>
	*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>A_v</math> is the voltage gain and <math>A_{v dB}</math> is the voltage gain is decibels.		*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>/ A_v</math> is the voltage gain and <math>/ A_{v dB}</math> is the voltage gain is decibels.

	==References==		==References==

Cdxskier: /* Decibel Conversion */

2010-01-26T00:43:03Z

Decibel Conversion

← Older revision		Revision as of 17:43, 25 January 2010
Line 23:		Line 23:

	<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>		<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>
	*By the equation above, we can say voltage gain in decibels is <math>\ A_{v dB}=20 log \|A_v\|</math>		*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>A_v</math> is the voltage gain and <math>A_{v dB}</math> is the voltage gain is decibels.



	==References==		==References==

← Older revision		Revision as of 11:51, 26 January 2010
Line 24:		Line 24:
	<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>		<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>
	*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.		*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.
	**For example, <math>\ 23 dbV = 14.12 V</math>
	*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.		*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.

← Older revision		Revision as of 11:50, 26 January 2010
Line 24:		Line 24:
	<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>		<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>
	*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.		*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.
			**For example, <math>/ 23 dbV = 14.12 V</math>
	*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.		*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.