Key Facts from Reading Chapter 1 - Revision history

Michaelvier at 03:24, 1 March 2010

2010-03-01T03:24:47Z

← Older revision		Revision as of 20:24, 28 February 2010
Line 38:		Line 38:

	==Contributors==		==Contributors==
	[[Lau, Chris \| Christopher Garrison Lau I]]		*[[Lau, Chris \| Christopher Garrison Lau I]]

	==Readers==		==Readers==
	[[Shepherd,Victor]]		*[[Shepherd,Victor]]

	==Reviewers==		==Reviewers==

	[[Ben Henry\|Henry,Ben]]		*[[Ben Henry\|Henry,Ben]]

	*[[Michael Vier\|Vier, Michael]]		*[[Michael Vier\|Vier, Michael]]

	*The sentence that says "voltage gain and is the voltage gain is decibels." I think you mean "in decibels." Other than that nice work!		*The sentence that says "voltage gain and is the voltage gain is decibels." I think you mean "in decibels." Other than that nice work!

Michaelvier at 03:24, 1 March 2010

2010-03-01T03:24:32Z

← Older revision		Revision as of 20:24, 28 February 2010
Line 47:		Line 47:
	[[Ben Henry\|Henry,Ben]]		[[Ben Henry\|Henry,Ben]]

	[[~~Ben Henry~~\|~~Henry~~,~~Ben~~]]		*[[Michael Vier\|Vier, Michael]]

	*The sentence that says "voltage gain and is the voltage gain is decibels." I think you mean "in decibels." Other than that nice work!		*The sentence that says "voltage gain and is the voltage gain is decibels." I think you mean "in decibels." Other than that nice work!

Michaelvier at 03:23, 1 March 2010

2010-03-01T03:23:57Z

← Older revision		Revision as of 20:23, 28 February 2010
Line 44:		Line 44:

	==Reviewers==		==Reviewers==

			[[Ben Henry\|Henry,Ben]]

	[[Ben Henry\|Henry,Ben]]		[[Ben Henry\|Henry,Ben]]

	*The sentence that says "voltage gain and is the voltage gain is decibels." I think you mean "in decibels." Other than that nice work!		*The sentence that says "voltage gain and is the voltage gain is decibels." I think you mean "in decibels." Other than that nice work!

Cdxskier: /* Decibel Conversion */

2010-02-08T09:45:21Z

Decibel Conversion

← Older revision		Revision as of 02:45, 8 February 2010
Line 25:		Line 25:
	<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>		<math>\ G_{db}=10 log \|A_v\|+10 log R_i - 10 log R_L</math>
	*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.		*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log \|A_v\|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.
	*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.		*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log \|A_i\|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain in decibels.

	==Differential Amplifiers==		==Differential Amplifiers==

Benjamin.henry: /* Readers */

2010-02-08T06:31:52Z

Readers

← Older revision		Revision as of 23:31, 7 February 2010
Line 42:		Line 42:
	==Readers==		==Readers==
	[[Shepherd,Victor]]		[[Shepherd,Victor]]

			==Reviewers==

			[[Ben Henry\|Henry,Ben]]

			*The sentence that says "voltage gain and is the voltage gain is decibels." I think you mean "in decibels." Other than that nice work!

Victor.shepherd: /* Contributors */

2010-02-05T06:01:04Z

Contributors

← Older revision		Revision as of 23:01, 4 February 2010
Line 39:		Line 39:
	==Contributors==		==Contributors==
	[[Lau, Chris \| Christopher Garrison Lau I]]		[[Lau, Chris \| Christopher Garrison Lau I]]

			==Readers==
			[[Shepherd,Victor]]

Cdxskier: /* Differential Amplifiers */

2010-02-01T00:38:29Z

Differential Amplifiers

← Older revision		Revision as of 17:38, 31 January 2010
Line 32:		Line 32:
	*The output of an ideal differential amplifier is given by <math>\ v_o=A_d v_{id} </math>.		*The output of an ideal differential amplifier is given by <math>\ v_o=A_d v_{id} </math>.
	*The common-mode input signal is given by the following: <math>v_{icm}=\frac{1}{2}(v_{i1}+v_{i2})</math>.		*The common-mode input signal is given by the following: <math>v_{icm}=\frac{1}{2}(v_{i1}+v_{i2})</math>.
	*A real differential amplifier's output is given by <math>\ v_o=A_d v_{id}+A_{cm} v_{icm} </math>, where <math>A_{cm}</math> is the common-mode signal gain.		*A real differential amplifier's output is given by <math>\ v_o=A_d v_{id}+A_{cm} v_{icm} </math>, where <math>\ A_{cm}</math> is the common-mode signal gain.

	==References==		==References==

Cdxskier: /* Amplifiers */

2010-02-01T00:33:18Z

Amplifiers

← Older revision		Revision as of 17:33, 31 January 2010
Line 13:		Line 13:
	*A noninverting amplifier has a positive voltage gain, <math>\ {A_{v}}</math>. (If you get this, you deserve a cookie)		*A noninverting amplifier has a positive voltage gain, <math>\ {A_{v}}</math>. (If you get this, you deserve a cookie)
	*The power gain,<math>\ G</math>, is the ration of the output power to the input power		*The power gain,<math>\ G</math>, is the ration of the output power to the input power
	**<math>G=\frac{P_{o}}{P_{i}}=\frac{V_o{I_o}}{~~V_o~~{~~I_o~~}}=A_v{A_{i}}=(A_v)^2\frac{R_{i}}{R_{L}}</math>		**<math>G=\frac{P_{o}}{P_{i}}=\frac{V_o{I_o}}{V_i{I_i}}=A_v{A_{i}}=(A_v)^2\frac{R_{i}}{R_{L}}</math>
	***<math>\ R_i</math> is the amplifier's input resistance and <math>\ R_o</math> is the amplifier's output resistance.		***<math>\ R_i</math> is the amplifier's input resistance and <math>\ R_o</math> is the amplifier's output resistance.

	==Decibel Conversion==		==Decibel Conversion==
	*Power gain, <math>\ G</math>, can be converted to decibels:		*Power gain, <math>\ G</math>, can be converted to decibels:

Cdxskier: New page: The following facts are not profound and are possibly very obvious. Nonetheless, they might help cement certain concepts. Please add things you think would be helpful. ==Transistors== [[...

2010-01-31T21:36:49Z

New page: The following facts are not profound and are possibly very obvious. Nonetheless, they might help cement certain concepts. Please add things you think would be helpful. ==Transistors== [[...

New page

The following facts are not profound and are possibly very obvious. Nonetheless, they might help cement certain concepts. Please add things you think would be helpful.
==Transistors==
[[Image:mosfet.jpg|thumb|right|400px|MOSFET diagram <ref> [http://www.msm.cam.ac.uk/doitpoms/tlplib/semiconductors/images/mosfet.jpg University of Cambridge] </ref>]]
*Conduction in n-type material is from free electrons.
*Conduction in p-type material is from holes (positive particles).
*The function of metal-oxide-semiconductor field-effect transistors (MOSFETs) depends on the voltage applied to the gate.
**Certain ranges of voltage allow no current to flow between the drain and the source. In this way, the MOSFET acts like an open switch.
**Another particular range of voltage allows current to easily flow from the source to the drain.
**When the voltage is in between the ranges of open and closed switch, the MOSFET can smoothly control the amount of current flowing.
*Bipolar Junction Transistors (BJTs) can act as either switches or current controls as well.
==Amplifiers==
*An inverting amplifier has a negative voltage gain, <math>\ {A_{v}}</math>.
*A noninverting amplifier has a positive voltage gain, <math>\ {A_{v}}</math>. (If you get this, you deserve a cookie)
*The power gain,<math>\ G</math>, is the ration of the output power to the input power
**<math>G=\frac{P_{o}}{P_{i}}=\frac{V_o{I_o}}{V_o{I_o}}=A_v{A_{i}}=(A_v)^2\frac{R_{i}}{R_{L}}</math>
***<math>\ R_i</math> is the amplifier's input resistance and <math>\ R_o</math> is the amplifier's output resistance.
==Decibel Conversion==
*Power gain, <math>\ G</math>, can be converted to decibels:

<math>G=(A_v)^2\frac{R_{i}}{R_{L}}</math>

<math>\ G_{db}=10 log{A_{v}}^2+10 log R_i - 10 log R_L</math>

<math>\ G_{db}=10 log |A_v|+10 log R_i - 10 log R_L</math>
*By the equation above, we can say voltage gain in decibels can be found with this equation: <math>\ A_{v dB}=20 log |A_v|</math>, where <math>\ A_v</math> is the voltage gain and <math>\ A_{v dB}</math> is the voltage gain is decibels.
*Similarly, we can say current gain in decibels can be found with this equation: <math>\ A_{i dB}=20 log |A_i|</math>, where <math>\ A_i</math> is the current gain and <math>\ A_{i dB}</math> is the current gain is decibels.

==Differential Amplifiers==
*Differential Amplifiers have two inputs. The terminal marked with a "+" is the noninverting input, and the terminal marked with a "-" is the inverting input.
*The differential input signal is given by <math>\ v_{id}=v_{i1}-v_{i2} </math>
*The output of an ideal differential amplifier is given by <math>\ v_o=A_d v_{id} </math>.
*The common-mode input signal is given by the following: <math>v_{icm}=\frac{1}{2}(v_{i1}+v_{i2})</math>.
*A real differential amplifier's output is given by <math>\ v_o=A_d v_{id}+A_{cm} v_{icm} </math>, where <math>A_{cm}</math> is the common-mode signal gain.

==References==
<references/>

==Contributors==
[[Lau, Chris | Christopher Garrison Lau I]]