Sherna at 09:35, 11 October 2006

2006-10-11T09:35:02Z

← Older revision		Revision as of 02:35, 11 October 2006
Line 1:		Line 1:
	~~Rayliegh~~'s Theorem is derived from the equation for Energy		Rayleigh's Theorem is derived from the equation for Energy
	*<math> W = \int_{-\infty}^{\infty}p(t)\,dt </math>		*<math> W = \int_{-\infty}^{\infty}p(t)\,dt </math>
	If we assume that the circuit is a Voltage applied over a load then <math> p(t)=\frac{x^2(t)}{R_L}</math>		If we assume that the circuit is a Voltage applied over a load then <math> p(t)=\frac{x^2(t)}{R_L}</math>

Sherna at 09:34, 11 October 2006

2006-10-11T09:34:15Z

@@ Line 1: / Line 1: @@
 Rayliegh's Theorem is derived from the equation for Energy
 *<math> W = \int_{-\infty}^{\infty}p(t)\,dt </math>
-If we assume that the circuit is a Thevin equavalent then  <math> p(t)=\frac{x^2(t)}{R_L}</math>
+If we assume that the circuit is a Voltage applied over a load then <math> p(t)=\frac{x^2(t)}{R_L}</math>
-for matters of simplicity we can assume <math>R_L = 1 \Omega</math>
+for matters of simplicity we can assume <math>R_L = 1\, \Omega</math>

Sherna at 05:07, 11 October 2006

2006-10-11T05:07:02Z

New page

Rayliegh's Theorem is derived from the equation for Energy
*<math> W = \int_{-\infty}^{\infty}p(t)\,dt </math>
If we assume that the circuit is a Thevin equavalent then <math> p(t)=\frac{x^2(t)}{R_L}</math>
for matters of simplicity we can assume <math>R_L = 1 \Omega</math>

Rayliegh's Theorem - Revision history

Sherna at 09:35, 11 October 2006

Sherna at 09:34, 11 October 2006

Sherna at 05:07, 11 October 2006