Transformer example problem - Revision history

Frohro: /* Part D: */

2010-02-04T20:25:43Z

Part D:

← Older revision		Revision as of 13:25, 4 February 2010
Line 68:		Line 68:

	<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>		<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>
	*Comment: There is a problem here in Part D, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = \frac{ N_1 I_1 } \mathcal{R} </math>and the flux, <math>{\Phi_2} ~=~ \frac{-N_2 I_2} {\mathcal{R}}</math> so that the total flux in any ideal transformer is zero.		*Comment: There is a problem here in Part D, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = \frac{ N_1 I_1 } \mathcal{R} </math>and the flux, <math>{\Phi_2} = \frac{-N_2 I_2} {\mathcal{R}}</math> so that the total flux in any ideal transformer is zero.

	==References:==		==References:==

Frohro: /* Part D: */

2010-02-04T20:25:21Z

Part D:

← Older revision		Revision as of 13:25, 4 February 2010
Line 68:		Line 68:

	<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>		<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>
	*Comment: There is a problem here in Part D, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }~~\frac~~ \mathcal{R} </math>and the flux, <math>{\Phi_2} ~=~ {-N_2 I_2}~~\frac~~ {\mathcal{R}}</math> so that the total flux in any ideal transformer is zero.		*Comment: There is a problem here in Part D, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = \frac{ N_1 I_1 } \mathcal{R} </math>and the flux, <math>{\Phi_2} ~=~ \frac{-N_2 I_2} {\mathcal{R}}</math> so that the total flux in any ideal transformer is zero.

	==References:==		==References:==

Frohro: /* Part D: */

2010-02-04T20:24:24Z

Part D:

← Older revision		Revision as of 13:24, 4 February 2010
Line 68:		Line 68:

	<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>		<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>
	*Comment: There is a problem here in Part D, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\~~over~~ \mathcal{R} </math>and the flux, <math>{\Phi_2} ~=~ {-N_2 I_2}\~~over~~ {\mathcal{R}}</math> so that the total flux in any ideal transformer is zero.		*Comment: There is a problem here in Part D, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\frac \mathcal{R} </math>and the flux, <math>{\Phi_2} ~=~ {-N_2 I_2}\frac {\mathcal{R}}</math> so that the total flux in any ideal transformer is zero.

	==References:==		==References:==

Frohro: /* Part D: */

2010-02-04T20:23:55Z

Part D:

← Older revision		Revision as of 13:23, 4 February 2010
Line 68:		Line 68:

	<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>		<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>
	*Comment: There is a problem here in Part D, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over \mathcal{R} </math>and the flux, <math>\Phi_2 ~=~ { -N_2 I_2 }\over {\mathcal{R}}</math> so that the total flux in any ideal transformer is zero.		*Comment: There is a problem here in Part D, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over \mathcal{R} </math>and the flux, <math>{\Phi_2} ~=~ {-N_2 I_2}\over {\mathcal{R}}</math> so that the total flux in any ideal transformer is zero.

	==References:==		==References:==

Frohro: /* Part D: */

2010-02-04T20:22:55Z

Part D:

← Older revision		Revision as of 13:22, 4 February 2010
Line 68:		Line 68:

	<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>		<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>
	*Comment: There is a problem here in Part D, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over R </math>and the flux, <math>\Phi_2 = { -N_2 I_2 }\over R</math> so that the total flux in any ideal transformer is zero.		*Comment: There is a problem here in Part D, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over \mathcal{R} </math>and the flux, <math>\Phi_2 ~=~ { -N_2 I_2 }\over {\mathcal{R}}</math> so that the total flux in any ideal transformer is zero.

	==References:==		==References:==

Frohro: /* Part D: */

2010-02-04T20:20:53Z

Part D:

← Older revision		Revision as of 13:20, 4 February 2010
Line 68:		Line 68:

	<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>		<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>
	*Comment: There is a problem here, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over R </math>and the flux, <math>\Phi_2 = { -N_2 I_2 }\over R</math> so that the total flux in any ideal transformer is zero.		*Comment: There is a problem here in Part D, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over R </math>and the flux, <math>\Phi_2 = { -N_2 I_2 }\over R</math> so that the total flux in any ideal transformer is zero.

	==References:==		==References:==

Frohro: /* Part D: */

2010-02-04T20:20:21Z

Part D:

← Older revision		Revision as of 13:20, 4 February 2010
Line 68:		Line 68:

	<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>		<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>
	*		*Comment: There is a problem here, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over R </math>and the flux, <math>\Phi_2 = { -N_2 I_2 }\over R</math> so that the total flux in any ideal transformer is zero.
	Comment:
	There is a problem here, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over R </math>and the flux, <math>\Phi_2 = { -N_2 I_2 }\over R</math> so that the total flux in any ideal transformer is zero.

	==References:==		==References:==

Frohro: /* Part D: */

2010-02-04T20:19:54Z

Part D:

← Older revision		Revision as of 13:19, 4 February 2010
Line 68:		Line 68:

	<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>		<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>
	--		*
	Comment:		Comment:
	There is a problem here, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over R </math>and the flux, <math>\Phi_2 = { -N_2 I_2 }\over R</math> so that the total flux in any ideal transformer is zero.		There is a problem here, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over R </math>and the flux, <math>\Phi_2 = { -N_2 I_2 }\over R</math> so that the total flux in any ideal transformer is zero.

Frohro: /* Part D: */

2010-02-04T20:19:30Z

Part D:

← Older revision		Revision as of 13:19, 4 February 2010
Line 68:		Line 68:

	<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>		<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>
	--Comment--		--
			Comment:
	There is a problem here, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over R </math>and the flux, <math>\Phi_2 = { -N_2 I_2 }\over R</math> so that the total flux in any ideal transformer is zero.		There is a problem here, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over R </math>and the flux, <math>\Phi_2 = { -N_2 I_2 }\over R</math> so that the total flux in any ideal transformer is zero.

Frohro: /* Part D: */

2010-02-04T20:18:11Z

Part D:

← Older revision		Revision as of 13:18, 4 February 2010
Line 68:		Line 68:

	<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>		<math> \ \Phi_m = \frac{120}{4.44 \cdot 60 \ Hz \cdot 75} \Rightarrow \Phi_m = 6.006 \ mWb </math>
			--Comment--
	There is a problem here, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over R </math>and the flux, <math>\Phi_2 = { -N_2 I_2 }\over R</math> so that the total flux in any ideal transformer is zero.		There is a problem here, because in an ideal transformer <math>N_1 I_1 = N_2 I_2</math> and the flux from <math>I_2</math> opposes the flux from <math>I_1</math>. Magnetic circuits tells us that the flux, <math>\Phi_1 = { N_1 I_1 }\over R </math>and the flux, <math>\Phi_2 = { -N_2 I_2 }\over R</math> so that the total flux in any ideal transformer is zero.