Integrator Amplifier: Difference between revisions
(7 intermediate revisions by 2 users not shown) | |||
Line 3: | Line 3: | ||
===Integrator === |
===Integrator === |
||
[[Image:Integrator_ben.jpg|200px|thumb|right|Graph of a typical Integrator Amp circuit (drawing redrawn by Ben Henry)]] |
[[Image:Integrator_ben.jpg|200px|thumb|right|Graph of a typical Integrator Amp circuit (drawing redrawn by Ben Henry)]] |
||
The circuit at right integrates the input voltage <math>V_{in}</math> by using an |
The circuit at right integrates the input voltage <math>V_{in}</math> by using an amplifier. |
||
<math>V_{out} = \frac{-1}{R_{1}*C}\int V_{in} dt |
<math>V_{out} = \frac{-1}{R_{1}*C}\int V_{in} dt |
||
Line 9: | Line 9: | ||
</math> |
</math> |
||
"<math>R_{2}</math> ; Provides negative feedback for low output impedance needs. But it also distorts the output."<sup>1</sup> |
"<math>R_{2}</math> ; Provides negative feedback for low output impedance needs. But it also distorts the output."<ref><sup>Quick Study "Electronics 1, Part 2"</sup></ref> |
||
The use of an |
The use of an integrator circuit is the opposite of a differentiator circuit. In other words, If you have a triangle wave input and you differentiate it you will get a square wave output. If you run the square wave as the input to an integrator circuit you will end up with the triangle wave for the output<ref><sup>Scherz, P: ''Practical Electronics for Inventors 2nd ed'', page 545. </sup></ref>. |
||
The |
The resistor (<math>R_{2}</math>) is used to provide feedback<ref><sup>[[Feedback_in_Amplifiers]]</sup></ref>. of the output DC voltage. Without this, circuit wouldn't perform as calculated because of the un-ideal conditions of real life. |
||
==Contributers== |
==Contributers== |
||
Line 18: | Line 18: | ||
--[[User:Benjamin.henry|Benjamin.henry]] 23:15, 10 January 2010 (UTC) |
--[[User:Benjamin.henry|Benjamin.henry]] 23:15, 10 January 2010 (UTC) |
||
== |
==Reviewers== |
||
[[Greg Fong]] |
[[Greg Fong]] |
||
[[Shepherd,Victor]] |
|||
*http://en.wikipedia.org/wiki/This_article_does_not_cite_any_references_or_sources.#Footnote_system |
|||
*I don't think I would capitalize amplifier, differentiator , differentiate, integrator or resistor. |
|||
*I believe you mean triangle wave and square wave, in place of ^^^ and square sine wave. |
|||
*After you take these comments into consideration, email me again and I'll take a look at it once more. |
|||
[[Greg Fong]] |
|||
I agree with Greg just like you did with square sine wave do the same with triangle wave instead of ^^^, makes it confusing and I don't believe that's a standard way of representing it. |
|||
*I will add one more thing. You don't need to have the types of waves within "". |
|||
==Sources== |
==Sources== |
||
<references/> |
|||
<sup>1</sup> Quick Study "Electronics 1, Part 2" |
|||
<sup>2</sup> Practical Electronics for Inventors (p545, 2nd edition) |
|||
<sup>3</sup> [[Feedback_in_Amplifiers]] |
Latest revision as of 09:39, 28 January 2010
Amplifiers
Integrator
The circuit at right integrates the input voltage by using an amplifier.
" ; Provides negative feedback for low output impedance needs. But it also distorts the output."<ref>Quick Study "Electronics 1, Part 2"</ref>
The use of an integrator circuit is the opposite of a differentiator circuit. In other words, If you have a triangle wave input and you differentiate it you will get a square wave output. If you run the square wave as the input to an integrator circuit you will end up with the triangle wave for the output<ref>Scherz, P: Practical Electronics for Inventors 2nd ed, page 545. </ref>. The resistor () is used to provide feedback<ref>Feedback_in_Amplifiers</ref>. of the output DC voltage. Without this, circuit wouldn't perform as calculated because of the un-ideal conditions of real life.
Contributers
--Benjamin.henry 23:15, 10 January 2010 (UTC)
Reviewers
Sources
<references/>