Integrator Amplifier: Difference between revisions

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===Integrator ===
===Integrator ===
[[Image:Integrator_ben.jpg|200px|thumb|right|Graph of a typical Integrator Amp circuit (drawing redrawn by Ben Henry)]]
[[Image:Integrator_ben.jpg|200px|thumb|right|Graph of a typical Integrator Amp circuit (drawing redrawn by Ben Henry)]]
The circuit at right integrates the input voltage <math>V_{in}</math> by using an Amplifier.
The circuit at right integrates the input voltage <math>V_{in}</math> by using an amplifier.


<math>V_{out} = \frac{-1}{R_{1}*C}\int V_{in} dt
<math>V_{out} = \frac{-1}{R_{1}*C}\int V_{in} dt
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</math>
</math>


"<math>R_{2}</math> ; Provides negative feedback for low output impedance needs. But it also distorts the output."<sup>1</sup>
"<math>R_{2}</math> ; Provides negative feedback for low output impedance needs. But it also distorts the output."<ref><sup>Quick Study "Electronics 1, Part 2"</sup></ref>


The use of an Integrator circuit is the opposite of a Differentiator circuit. In other words, If you have a "^^^" style input and you Differentiate it you will get a "square sine wave" output. If you run the "square sine wave" as the input to an Integrator circuit you will end up with the "^^^" for the output<sup>2</sup>.
The use of an integrator circuit is the opposite of a differentiator circuit. In other words, If you have a triangle wave input and you differentiate it you will get a square wave output. If you run the square wave as the input to an integrator circuit you will end up with the triangle wave for the output<ref><sup>Scherz, P: ''Practical Electronics for Inventors 2nd ed'', page 545. </sup></ref>.
The Resistor (<math>R_{2}</math>) Is used to provide feedback<sup>3</sup> of the output DC voltage. Without this, circuit wouldn't perform as calculated because of the un-ideal conditions of real life.
The resistor (<math>R_{2}</math>) is used to provide feedback<ref><sup>[[Feedback_in_Amplifiers]]</sup></ref>. of the output DC voltage. Without this, circuit wouldn't perform as calculated because of the un-ideal conditions of real life.


==Contributers==
==Contributers==
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--[[User:Benjamin.henry|Benjamin.henry]] 23:15, 10 January 2010 (UTC)
--[[User:Benjamin.henry|Benjamin.henry]] 23:15, 10 January 2010 (UTC)


==Readers==
==Reviewers==
[[Greg Fong]]
[[Greg Fong]]
[[Shepherd,Victor]]
*http://en.wikipedia.org/wiki/This_article_does_not_cite_any_references_or_sources.#Footnote_system
*I don't think I would capitalize amplifier, differentiator , differentiate, integrator or resistor.
*I believe you mean triangle wave and square wave, in place of ^^^ and square sine wave.
*After you take these comments into consideration, email me again and I'll take a look at it once more.

[[Greg Fong]]
I agree with Greg just like you did with square sine wave do the same with triangle wave instead of ^^^, makes it confusing and I don't believe that's a standard way of representing it.
*I will add one more thing. You don't need to have the types of waves within "".


==Sources==
==Sources==
<references/>

<sup>1</sup> Quick Study "Electronics 1, Part 2"

<sup>2</sup> Practical Electronics for Inventors (p545, 2nd edition)

<sup>3</sup> [[Feedback_in_Amplifiers]]

Latest revision as of 09:39, 28 January 2010

Amplifiers

Integrator

Graph of a typical Integrator Amp circuit (drawing redrawn by Ben Henry)

The circuit at right integrates the input voltage by using an amplifier.

" ; Provides negative feedback for low output impedance needs. But it also distorts the output."<ref>Quick Study "Electronics 1, Part 2"</ref>

The use of an integrator circuit is the opposite of a differentiator circuit. In other words, If you have a triangle wave input and you differentiate it you will get a square wave output. If you run the square wave as the input to an integrator circuit you will end up with the triangle wave for the output<ref>Scherz, P: Practical Electronics for Inventors 2nd ed, page 545. </ref>. The resistor () is used to provide feedback<ref>Feedback_in_Amplifiers</ref>. of the output DC voltage. Without this, circuit wouldn't perform as calculated because of the un-ideal conditions of real life.

Contributers

--Benjamin.henry 23:15, 10 January 2010 (UTC)

Reviewers

Greg Fong Shepherd,Victor

Sources

<references/>