An Ideal Transformer Example: Difference between revisions

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<math>\ {e_{1}}(t)={V_{1}}\cos(\omega t)</math> and <math>\ \omega=2\pi f</math>
<math>\ {e_{1}}(t)={V_{1}}\cos(\omega t)</math> and <math>\ \omega=2\pi f</math>


Substituting <math>\ f = 60Hz, <math>\ \omega=120\pi</math>
Substituting <math>\ f = 60Hz</math>, <math>\ \omega=120\pi</math>


Therefore, <math>\ {e_{1}}(t)=120\sqrt{2}\cos(120\pi t)V</math>
Therefore, <math>\ {e_{1}}(t)=120\sqrt{2}\cos(120\pi t)V</math>

Revision as of 10:48, 21 January 2010

Consider a simple, transformer with two windings. Find the current provided by the voltage source.

  • Winding 1 has a sinusoidal voltage of ° applied to it at a frequency of 60Hz.
  • The combined load on winding 2 is

Solution

Given: and

Substituting ,

Therefore,

Now the Thevenin equivalent impedance, , is found through the following steps:

Now, substituting:

Since ,

Since this is an ideal transformer, it can be modeled by this simple circuit: Ideal Circuit.jpg

Contributors

Christopher Garrison Lau I

Reviwed By

Andrew Sell - Chris, everything looks fine, though I would do some extra formatting if possible to help make the problem flow a little smoother as you read it, and locate the picture a little higher to help bring the solution together.

Read By

John Hawkins