ASN6c - Fourier Transform property: Value at origin: Difference between revisions

Latest revision as of 13:40, 19 December 2009

This Fourier Transform property says $s(0)\!$ becomes $\int _{-\infty }^{\infty }S(f)df$

$s(0)=s(t)|_{t=0}={\mathcal {F}}^{-1}\left[S(f)\right])|_{t=0}$

Evaluating the inverse Fourier transform at time zero

$s(0)=\int _{-\infty }^{\infty }S(f)e^{j2\pi f(0)}df=\int _{-\infty }^{\infty }S(f)df$

Therefore this process shows that $s(0)\!$ is $\int _{-\infty }^{\infty }S(f)df$

Revision as of 13:39, 19 December 2009 (view source) Jodi.Hodge (talk \| contribs) No edit summary ← Older edit		Latest revision as of 13:40, 19 December 2009 (view source) Jodi.Hodge (talk \| contribs) No edit summary
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	<math>s(0) = \int_{-\infty}^{\infty} S(f)e^{ j 2 \pi f(0) } df = \int_{-\infty}^{\infty} S(f) df</math>		<math>s(0) = \int_{-\infty}^{\infty} S(f)e^{ j 2 \pi f(0) } df = \int_{-\infty}^{\infty} S(f) df</math>

	~~This~~ shows ~~how~~ <math>s(0) \!</math> ~~becomes~~ <math>\int_{-\infty}^{\infty} S(f) df</math>		Therefore this process shows that <math>s(0) \!</math> is <math>\int_{-\infty}^{\infty} S(f) df</math>