Complex vector inner products: Difference between revisions
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In order to preserve the property that the inner product of any vector with itself is the magnitude of that vector squared, we need to define the inner product of complex vectors so that |
In order to preserve the property that the inner product of any vector with itself is the magnitude of that vector squared, we need to define the inner product of complex vectors so that |
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<math> \vec \bold u \bullet \vec \bold v = sum_{k=1}^n u_k v_k^* </math> |
<math> \vec \bold u \bullet \vec \bold v = \sum_{k=1}^n u_k v_k^* </math> |
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where we have assumed that the basis vectors are orthonormal and that there are <math>n</math> dimensions. Some define the conjugate on the first vector instead of the secon, but in order to be consistent with bra-ket notation from quantum mechanics, we do it with the conjugate on the second vector. |
where we have assumed that the basis vectors are orthonormal and that there are <math>n</math> dimensions. Some define the conjugate on the first vector instead of the secon, but in order to be consistent with bra-ket notation from quantum mechanics, we do it with the conjugate on the second vector. |
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With this we have |
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and |
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<math>\vec \bold v \bullet \vec \bold v = |\vec \bold v | ^2</math>. |
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Revision as of 12:15, 24 September 2004
Complex Vector Inner Products
In order to preserve the property that the inner product of any vector with itself is the magnitude of that vector squared, we need to define the inner product of complex vectors so that
where we have assumed that the basis vectors are orthonormal and that there are dimensions. Some define the conjugate on the first vector instead of the secon, but in order to be consistent with bra-ket notation from quantum mechanics, we do it with the conjugate on the second vector.
With this we have
and
.
