Coupled Horizontal Spring Mass Oscillator: Difference between revisions

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</math>,<math>\ {K_2=}\,</math><math>\begin{bmatrix}-1 \\2\sqrt(10) \\1 \\-2\sqrt(10)\end{bmatrix}\,
</math>,<math>\ {K_2=}\,</math><math>\begin{bmatrix}-1 \\2\sqrt(10) \\1 \\-2\sqrt(10)\end{bmatrix}\,
</math>,<math>\ {K_3=}\,</math><math>\begin{bmatrix}1 \\2\sqrt(5) \\1 \\2\sqrt(5)\end{bmatrix}\,
</math>,<math>\ {K_3=}\,</math><math>\begin{bmatrix}1 \\2\sqrt(5) \\1 \\2\sqrt(5)\end{bmatrix}\,
</math>,<math>\ {K_4=}\,</math><math>\begin{bmatrix}1 \\-2\sqrt(5) \\1 \\-2\sqrt(5)\end{bmatrix}\,
</math>
</math>

Revision as of 16:35, 8 December 2009

Coupled Oscillator Spring Mass Oscillator: State Space

Problem Statement

Two 4 Kg Weights are suspended between two walls. They are connected by a spring between them with a spring constant k2. They are connected to the walls by two springs k1 and k3 with k1=k3. m1 is a distance x1 form m2 and m2 is x2 from the wall.


Solution

Things we know

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