EMEC: Difference between revisions

Revision as of 11:52, 18 January 2010

$r_{m}=({\frac {1}{2}}){\frac {OD+ID}{2}}$

$H_{m}=({\frac {Ni}{l_{m}}})$

$H_{m}=({\frac {20x2.5}{.141}}=354.6A/m)$

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	<math>H_m=(\frac{Ni}{l_m})</math>		<math>H_m=(\frac{Ni}{l_m})</math>

	<math>H_m=(\frac{20 X 2.5}{})</math>		<math>H_m=(\frac{20 x 2.5}{.141}= 354.6 A/m)</math>