Revision as of 16:29, 10 January 2010

Amplifiers

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The circuit at right integrates the input voltage $V_{in}$ .

$V_{out}={\frac {-1}{R_{1}*C}}\int V_{in}dt$

" $R_{2}$ ; Provides negative feedback for low output impedance needs. But it also distorts the output."¹

--Benjamin.henry 23:15, 10 January 2010 (UTC)

¹ Quick Study "Electronics 1, Part 2"

@@ Line 11: / Line 11: @@
 "<math>R_{2}</math> ; Provides negative feedback for low output impedance needs. But it also distorts the output."<sup>1</sup>
-===Linear Voltage to Current Converters===
 ==Contributers==