HW 04: Difference between revisions

Revision as of 02:05, 17 November 2008

$\overbrace {10[u(t-2)-u(t-3)]} ^{x(t)}*\overbrace {e^{-t}u(t)} ^{h(t)}=$

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	<math>\overbrace{10 [u(t-2) - u(t-3)]}^{x(t)} * \overbrace{e^{-t}u(t)}^{h(t)}~~</math>~~		<math>\overbrace{10 [u(t-2) - u(t-3)]}^{x(t)} * \overbrace{e^{-t}u(t)}^{h(t)} =

			</math>