Homework Seven: Difference between revisions

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Imagine we have an original signal that has the following frequency plot, centered about the "zero frequency" origin:
Imagine we have an original signal that has the following frequency plot, centered about the "zero frequency" origin:


[[Image:original.jpg |thumb|center|upright=2|Figure 1:Original signal for which we want to analyze.]]
[[Image:original.jpg |thumb|center|upright=2|Figure 1: Original signal for which we want to analyze.]]

In order to analyze this signal we must look at both the positive and negative frequency aspects -- therefore, we will split the signal into two parts, positive and negative:
In order to analyze this signal we must look at both the positive and negative frequency aspects -- therefore, we will split the signal into two parts, positive and negative:


[[Image:signal_split.jpg |thumb|center|upright=2|Figure 1:Original signal for which we want to analyze.]]
[[Image:signal_split.jpg |thumb|center|upright=2|Figure 2: Signal separated into positive and negative aspects.]]


To "send the signal" we must essentially move it to a higher frequency and, remembering that x(t) has frequency components for <math>\textstyle \frac{1}{2}f_{s} < f < f_{s}</math>, we get the following signal, <math> \textstyle X(f) </math>:
To "send the signal" we must essentially move it to a higher frequency and, remembering that x(t) has frequency components for <math>\textstyle \frac{1}{2}f_{s} < f < f_{s}</math>, we get the following signal, <math> \textstyle X(f) </math>:


[[Image:signal_export.jpg |thumb|center|upright=2|Figure 1:Original signal for which we want to analyze.]]
[[Image:signal_export.jpg |thumb|center|upright=2|Figure 3: Preparing signal to be sent and sampled.]]


Finally, we need to sample the signal at a rate of <math>\textstyle f_s = \frac{1}{T} </math>. Theoretically, this leads to the following frequency plot:
Finally, we need to sample the signal at a rate of <math>\textstyle f_s = \frac{1}{T} </math>. Theoretically, this leads to the following frequency plot:


[[Image:signal_sampled.jpg |thumb|center|upright=2|Figure 1:Original signal for which we want to analyze.]]
[[Image:signal_sampled.jpg |thumb|center|upright=2|Figure 4: Signal being sampled at a rate of 1/T.]]


In order to get the original signal, we simply need to create a lowpass filter that will essentially encompass the the original (desired) signal:
In order to get the original signal, we simply need to create a lowpass filter that will essentially encompass the the original (desired) signal:


[[Image:signal_lowpass.jpg |thumb|center|upright=2|Figure 1:Original signal for which we want to analyze.]]
[[Image:signal_lowpass.jpg |thumb|center|upright=2|Figure 5: The use of a lowpass filter to obtain the original signal as shown in Figure 1.]]


So what have we accomplished? We have taken a signal (Figure 1), prepared it to be analyzed and sampled (Figure 2 & 3), sampled it at a sampling rate of <math>\textstyle f_s = \frac{1}{T} </math> (Figure 4), and used a lowpass filter to collect the original (now sampled) signal (Figure 5).
So what have we accomplished? We have taken a signal (Figure 1), prepared it to be sampled (Figure 2 & 3), sampled it at a sampling rate of <math>\textstyle f_s = \frac{1}{T} </math> (Figure 4), and used a lowpass filter to collect the original (now sampled) signal (Figure 5).

Revision as of 12:57, 29 November 2009

Figure out what happens if your sampled signal, x(t), has frequency components only for . Can you recover the original signal from it? If so, find the expression for x(t) in terms of x(nt).


Nick Christman


Imagine we have an original signal that has the following frequency plot, centered about the "zero frequency" origin:

Figure 1: Original signal for which we want to analyze.

In order to analyze this signal we must look at both the positive and negative frequency aspects -- therefore, we will split the signal into two parts, positive and negative:

Figure 2: Signal separated into positive and negative aspects.

To "send the signal" we must essentially move it to a higher frequency and, remembering that x(t) has frequency components for , we get the following signal, :

Figure 3: Preparing signal to be sent and sampled.

Finally, we need to sample the signal at a rate of . Theoretically, this leads to the following frequency plot:

Figure 4: Signal being sampled at a rate of 1/T.

In order to get the original signal, we simply need to create a lowpass filter that will essentially encompass the the original (desired) signal:

Figure 5: The use of a lowpass filter to obtain the original signal as shown in Figure 1.

So what have we accomplished? We have taken a signal (Figure 1), prepared it to be sampled (Figure 2 & 3), sampled it at a sampling rate of (Figure 4), and used a lowpass filter to collect the original (now sampled) signal (Figure 5).