Matthew's Asgn: Difference between revisions

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[[File:RLcircuit.jpg]]
[[File:RLcircuit.jpg]]


The Laplace transform for an inductor
The Laplace transform for an inductor:


<math>\displaystyle\mathcal{L} \left\{f(t)\right\}</math> = <math>\ Ls + Li \,\!</math>
<math>\displaystyle\mathcal{L} \left\{f(t)\right\}</math> = <math>\ Ls + Li \,\!</math>


The Laplace transform for a resistor is just the resistor itself
The Laplace transform for a resistor:


<math>\displaystyle\mathcal{L} \left\{f(t)\right\}</math> = <math>\ R\,\!</math>
<math>\displaystyle\mathcal{L} \left\{f(t)\right\}</math> = <math>\ R\,\!</math>
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<math>\ 0 = -s/(s^2+w^2) + RI(s) + LsI(s) - Li \,\!</math>
<math>\ 0 = -s/(s^2+w^2) + RI(s) + LsI(s) - Li \,\!</math>

A series of algebraic manipulations follows to come up with I(s):


<math>\ s/(s^2+w^2) = (R+Ls)I(s) + Li \,\!</math>


<math>\ I(s) = s/((s^2+w^2)(R+Ls)) - Li/(R+Ls) \,\!</math>

Revision as of 17:09, 1 November 2010

I decided that I would attempt to perform a simple analysis of a series RL circuit, which could then be used to do a more complex analysis on a basic transformer. I have always had interest in electronics, and transformers are key to basic electronics.

I decided that i would do the analysis of a RL circuit with the variables instead of given values.


Given:

V(t)=

V(s)=

I(0)=i

RLcircuit.jpg

The Laplace transform for an inductor:

=

The Laplace transform for a resistor:

=

Therefore the Resulting Equation for the system after applying the Laplace Transform:

A series of algebraic manipulations follows to come up with I(s):