Matthew's Asgn: Difference between revisions

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<math>\ I(s) = s/((s^2+w^2)(R+Ls)) - Li/(R+Ls) \,\!</math>
<math>\ I(s) = \dfrac{s}{(s^2+w^2)(R+Ls)} - \dfrac{Li}{(R+Ls)} \,\!</math>

We can then use partial fraction manipulation to expand the expression:

<math>\ s/((s^2+w^2)(R+Ls)) = A/(s+jw) + A*/(s-jw) + B/(Ls+R) \,\!</math>

<math>\ (s/L)/((s^2+w^2)(R/L+s)) = (A(s+jw)(s+R/L))/((s+R/L)(s^2+w^2)) + (A*(s+jw)(s+R/L))/((s^2+w^2)(s+R/L)) + (B(s^2+w^2))/((s+R/L)(s^2+w^2)) \,\!</math>

<math>\ S/L = A((s-jw)(s+R/L)) + A*((s+jw)(s+R/L)) + B(s^2+w^2)

= A(s^2-jws+R/Ls-jwR/L) + a*(s^2+jws+R/L+jwr/L) + B(s^2+w^2) \,\!</math>

Revision as of 17:31, 1 November 2010

I decided that I would attempt to perform a simple analysis of a series RL circuit, which could then be used to do a more complex analysis on a basic transformer. I have always had interest in electronics, and transformers are key to basic electronics.

I decided that i would do the analysis of a RL circuit with the variables instead of given values.


Given:

V(t)=

V(s)=

I(0)=i

RLcircuit.jpg

The Laplace transform for an inductor:

=

The Laplace transform for a resistor:

=

Therefore the Resulting Equation for the system after applying the Laplace Transform:

A series of algebraic manipulations follows to come up with I(s):



We can then use partial fraction manipulation to expand the expression: