Problem Set 1: Difference between revisions

From Class Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Line 33: Line 33:
<math>S^{2}=P^{2}+Q^{2}\!</math>
<math>S^{2}=P^{2}+Q^{2}\!</math>


Use the apparent power and the real power to find the reactive power
Solve the above equation for reactive power using the values of apparent and real power.


<math>Q=\sqrt{S^{2}-P^{2}}= \sqrt{225^{2}-10^{2}}= 224.8VAr\!</math> Answer
<math>Q=\sqrt{S^{2}-P^{2}}= \sqrt{225^{2}-10^{2}}= 224.8VAr\!</math>


Reactive power is stored in non-linear impedance represented as X. In this case X is inductance.
Reactive power is stored in non-linear impedance represented as X. In this case X is inductance.
Line 41: Line 41:
<math>Q=Voc^{2}/X\!</math>
<math>Q=Voc^{2}/X\!</math>


<math>X=Voc^{2}/Q=5V^{2}/224.8VAr=0.11H \!</math>
<math>X=Voc^{2}/Q=5V^{2}/224.8VAr=0.11H \!</math> Answer

Revision as of 23:41, 8 February 2010

Problem


Find the core inductance and resistance of a transformer using measurements Voc=5V, Ioc=3A, and Poc =10W.


Solution

Power is stored in resistors because of their linear behavior.

Both Poc and Voc are giving so solve for R

Answer

Apparent power relation to voltage and current is

The magnitude for current and voltage are given in the problem statement. Subtitute in known values and solve.

Apparent power S is complex. It has a real part P, real power, and an imaginary part Q, reactive power.

Apparent power in the imaginary and real coordinate system is the hypotenuse of real and reactive power and can be expressed using the equation of a circle.

Solve the above equation for reactive power using the values of apparent and real power.

Reactive power is stored in non-linear impedance represented as X. In this case X is inductance.

Answer