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Find <math>\overbrace{10 [u(t-2) - u(t-3)]}^{x(t)} * \overbrace{e^{-t}u(t)}^{h(t)}</math>

[[Image:HW4.PNG]]

<math>10 [u(t-2) - u(t-3)] * e^{-t}u(t) = 
\begin{cases}
0, & t \le 2 \\
\int_{0}^{t-2} 10 \cdot e^{-t} \,d\lambda, & t > 2\\
\end{cases} </math>

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