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First, a digital signal <math>x(kt)</math> read from the CD is convolved with a pulse function <math>p(t)</math> and the result looks like this
First, a digital signal <math>x(kt)</math> is read from the CD adn then convolved with a pulse function <math>p(t)</math>. The result in the time domain looks like this:


<center>
[[Image:DAOutput.jpg|Description]]
[[Image:DAOutput.jpg|Description]]


<math>
<math>
\hat x(t) = \sum_{k=-\infty}^\infty x(kT)p(t - kT) = p(t) *\sum_{k=-\infty}^\infty x(kT) \delta (t - kT)
</math>
</center>
Let's look at this is frequency space. Note that convolution in time means multiplication in frequency.


<center>
<math>\hat X(f) = 1/T \sum_{n=-\infty}^\infty X(f - n/T) \cdot P(f)</math>
</center>
where
<center>
<math>P(f) = \int_{-T/2}^{T/2} e^{j2\pi ft} \, dt = T sinc(fT)
</math>
</math>
</center>
The low pass filter then knocks the high frequencies out of the signal to be sent to the speaker.

Revision as of 19:54, 6 December 2004

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Aric Goe

Signals & Systems

Introduction

Becoming familiar with Wiki

Well, it all seems a little too convenitent to me.

Practicing TEX

Simple Transformer Equation
EpTp=EsTs

How a CD Player Works

Description


First, a digital signal x(kt) is read from the CD adn then convolved with a pulse function p(t). The result in the time domain looks like this:


Description

x^(t)=k=x(kT)p(tkT)=p(t)*k=x(kT)δ(tkT)


Let's look at this is frequency space. Note that convolution in time means multiplication in frequency.


X^(f)=1/Tn=X(fn/T)P(f)

where

P(f)=T/2T/2ej2πftdt=Tsinc(fT)

The low pass filter then knocks the high frequencies out of the signal to be sent to the speaker.