Signals and systems/GF Fourier: Difference between revisions

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*<math> (a+jb)\hat i \cdot (a-jb)\hat i = a^2+b^2 </math>
*<math> (a+jb)\hat i \cdot (a-jb)\hat i = a^2+b^2 </math>
To test for orthogonality, take the complex conjugate of one of the vectors and multiply.
*<math> \int_{-\infty}^{\infty} \phi_n (t) \phi_m^* (t) dt = 0</math>


==Changing Basis Functions==
==Changing Basis Functions==

Revision as of 23:36, 29 October 2006

Fourier series

The Fourier series is used to analyze arbitrary periodic functions by showing them as a composite of sines and cosines.

A function is considered periodic if x(t)=x(t+T) for T0.

The exponential form of the Fourier series is defined as x(t)=n=αnej2πnt/T

Determining the coefficient αn

x(t)=n=αnej2πnt/T

  • The definition of the Fourier series

T/2T/2x(t)dt=n=αnT/2T/2ej2πnt/Tdt

  • Integrating both sides for one period. The range of integration is arbitrary, but using T/2T/2 scales nicely when extending the Fourier series to a non-periodic function

T/2T/2x(t)ej2πmt/Tdt=n=αnT/2T/2ej2πnt/Tej2πmt/Tdt=n=αnT/2T/2ej2π(nm)t/Tdt

  • Multiply by the complex conjugate

T/2T/2x(t)ej2πmt/Tdt=n=αnTej2π(nm)t/Tj2π(nm)|T/2T/2=n=αnTδn,m=Tαm

  • Tej2π(nm)t/Tj2π(nm)|T/2T/2=Tejπ(nm)ejπ(nm)j2π(nm)=Tsinπ(nm)π(nm)={T,n=m0,nm}=Tδn,m
    • Using L'Hopitals to evaluate the T00 case. Note that n & m are integers

αm=1TT/2T/2x(t)ej2πmt/Tdt


Linear Time Invariant Systems

Must meet the following criteria

  • Time independance
  • Linearity
    • Superposition (additivity)
    • Scaling (homogeneity)

The Dot Product, Complex Conjugates, and Orthogonality

File:300px-Scalarproduct.gif

Geometrically, the dot product is a scalar projection of a onto b

  • ab=|a||b|cosθ

Arthimetically, multiply like terms and add

  • (3,2,1)(5,6,7)=35*+26*+17*

Lets imagine that we are only have one dimension

  • (a+jb)i^(a+jb)i^a2+b2

In order to get the real parts and imaginary parts to multiply as like terms, we need to take the complex conjugate of one of the terms

  • (a+jb)i^(ajb)i^=a2+b2

To test for orthogonality, take the complex conjugate of one of the vectors and multiply.

  • ϕn(t)ϕm*(t)dt=0

Changing Basis Functions

Identities

ejθ=cosθ+jsinθ

sinx=ejxejx2j

cosx=ejx+ejx2

BraKet=KetBra

αm=α*

The dirac delta has an infinite height and an area of 1