Vector weighting functions: Difference between revisions

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===Orthogonal but not Orthonormal Basis Sets===
===Orthogonal but not orthonormal basis sets===


Suppose we have two vectors from an orthonormal system, <math> \vec \bold u </math> and <math> \vec \bold v </math>.  Taking the inner product of these vectors, we get
Suppose we have two vectors from an orthonormal system, <math> \vec \bold u </math> and <math> \vec \bold v </math>.  Taking the inner product of these vectors, we get
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<math> \vec \bold u \bullet \vec \bold v = \sum_{k=1}^3 u_k \vec \bold a_k \bullet \sum_{m=1}^3 v_m \vec \bold a_m  = \sum_{k=1}^3 u_k \sum_{m=1}^3  v_m \vec \bold a_k \bullet  \vec \bold a_m = \sum_{k=1}^3 u_k \sum_{m=1}^3  v_m w_k\delta_{k,m} = \sum_{k=1}^3 w_k v_k u_k </math>.
<math> \vec \bold u \bullet \vec \bold v = \sum_{k=1}^3 u_k \vec \bold a_k \bullet \sum_{m=1}^3 v_m \vec \bold a_m  = \sum_{k=1}^3 u_k \sum_{m=1}^3  v_m \vec \bold a_k \bullet  \vec \bold a_m = \sum_{k=1}^3 u_k \sum_{m=1}^3  v_m w_k\delta_{k,m} = \sum_{k=1}^3 w_k v_k u_k </math>.


You can interpret the <math>w_k</math> as a weighting factor between the different directions so that different directions all end up in the units you would like.  For example, suppose that the x and y directions were measured in meters, and the z direction was measured in centimeters, and you would like to use meters as your base unit.  You could either convert the z dimensions to meters (probably simpler) or use a weighting function <math> w_x = 1</math>, <math>w_y = 1</math> and <math> w_z = 10^{-6} </math>.
You can interpret the <math>w_k</math> as a weighting factor between the different directions so that different directions all end up in the units you would like.  For example, suppose that the x and y directions were measured in meters, and the z direction was measured in centimeters, and you would like to use meters as your base unit.  You could either convert the z dimensions to meters (probably simpler) or use a weighting function <math> w_x = 1</math>, <math>w_y = 1</math> and <math> w_z = 10^{-6} </math>. In this sense, the system could be considered orthonormal with these units and this weighting arrangement.
 
[[Orthogonal Functions|This idea is often extended to functions.]]
 
[[Orthogonal functions]]
 
Principle author of this page:  [[User:Frohro|Rob Frohne]]

Latest revision as of 17:36, 26 September 2004

Orthogonal but not orthonormal basis sets

Suppose we have two vectors from an orthonormal system, u and v. Taking the inner product of these vectors, we get

uv=k=13ukakm=13vmam=k=13ukm=13vmakam=k=13ukm=13vmδk,m=k=13vkuk

What if they aren't from a normalized system, so that

akan=wkδk,n

where the wk is the square of the length of ak and the symbol δk,n is one when k = n and zero otherwise? Well the general inner product of u and v becomes

uv=k=13ukakm=13vmam=k=13ukm=13vmakam=k=13ukm=13vmwkδk,m=k=13wkvkuk.

You can interpret the wk as a weighting factor between the different directions so that different directions all end up in the units you would like. For example, suppose that the x and y directions were measured in meters, and the z direction was measured in centimeters, and you would like to use meters as your base unit. You could either convert the z dimensions to meters (probably simpler) or use a weighting function wx=1, wy=1 and wz=106. In this sense, the system could be considered orthonormal with these units and this weighting arrangement.

This idea is often extended to functions.

Orthogonal functions

Principle author of this page: Rob Frohne