Laplace transforms: Critically Damped Motion: Difference between revisions
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Mark.bernet (talk | contribs) |
Mark.bernet (talk | contribs) |
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<math>\text {Damping constant C=2}\,</math> |
<math>\text {Damping constant C=2}\,</math> |
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Therefore the equation representing this system is |
<math>\text {Therefore the equation representing this system is}\,</math> |
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<math>\frac{d^2x}{dt^2}=-4x-2\frac{dx}{dt}</math> |
<math>\frac(1)(4)frac{d^2x}{dt^2}=-4x-2\frac{dx}{dt}</math> |
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<math>\text { |
<math>\text {Now we put the equation in standard form}\,</math> |
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<math>\frac{d^2x}{dt^2}+4x-2\frac{dx}{dt}</math> |
Revision as of 17:22, 22 October 2009
Using the Laplace Transform to solve a spring mass system that is critically damped
Problem Statement
An 8 pound weight is attached to a spring with a spring constant k of 4 lb/ft. The spring is stretched 2 ft and rests at its equilibrium position. It is then released from rest with an initial upward velocity of 3 ft/s. The system contains a damping force of 2 times the initial velocity.
Solution
Things we know