Laplace transforms: Critically Damped Motion: Difference between revisions

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<math>\text {Damping constant C=2}\,</math>
<math>\text {Damping constant C=2}\,</math>


Therefore the equation representing this system is
<math>\text {Therefore the equation representing this system is}\,</math>


<math>\frac{d^2x}{dt^2}=-4x-2\frac{dx}{dt}</math>
<math>\frac(1)(4)frac{d^2x}{dt^2}=-4x-2\frac{dx}{dt}</math>


<math>\text {now we put the equation in standard form}\,</math>
<math>\text {Now we put the equation in standard form}\,</math>

<math>\frac{d^2x}{dt^2}+4x-2\frac{dx}{dt}</math>

Revision as of 17:22, 22 October 2009

Using the Laplace Transform to solve a spring mass system that is critically damped

Problem Statement

An 8 pound weight is attached to a spring with a spring constant k of 4 lb/ft. The spring is stretched 2 ft and rests at its equilibrium position. It is then released from rest with an initial upward velocity of 3 ft/s. The system contains a damping force of 2 times the initial velocity.

Solution

Things we know