7 - Sampling a Signal: Difference between revisions

From Class Wiki
Jump to navigation Jump to search
(New page: Figure out what happens if your sampled signal, x(t), has frequency components only for <math>\textstyle \frac{1}{2}f_{s} < f < f_{s}</math>. Can you recover the original signal from it? I...)
 
No edit summary
Line 1: Line 1:
Figure out what happens if your sampled signal, x(t), has frequency components only for <math>\textstyle \frac{1}{2}f_{s} < f < f_{s}</math>. Can you recover the original signal from it? If so, find the expression for x(t) in terms of x(nt) <br><br>
Figure out what happens if your sampled signal, x(t), has frequency components only for <math>\textstyle \frac{1}{2}f_{s} < f < f_{s}</math>. Can you recover the original signal from it? If so, find the expression for x(t) in terms of x(nt) <br><br>

In this problem we are going to sample a signal as shown below where <math>\textstyle f_{s} = 1/T</math>

[[Image:Hw7-1.JPG]] <br>

When we sample the signal at <math>\textstyle f_{s}</math> The signal repeats every <math>\textstyle f_{s}</math> yielding <br>

[[Image:Hw7-2.JPG]] <br>

Now to get the original signal back all we need to do is us a filter to eliminate everything we don't want. I this case depending on what we want we can either take the centered frequency which is usually done in a receiver since a broad casted signal is usually broken up into a positive and negative component as seen in the original figure or we can just take the broken apart signal that we started with as seen below

[[Image:Hw7-3.JPG]] <br>

Notice if <math>\textstyle f > \frac{1}{2}f_{s}</math> we couldn't get the original signal after sampling because the signals would overlap as seen below


[[Image:Hw7-4.JPG]] <br>

Now that we can see that the original signal is recoverable lets look at x(t) in terms of x(nt) <br><br>

Revision as of 09:43, 1 December 2009

Figure out what happens if your sampled signal, x(t), has frequency components only for . Can you recover the original signal from it? If so, find the expression for x(t) in terms of x(nt)

In this problem we are going to sample a signal as shown below where

Hw7-1.JPG

When we sample the signal at The signal repeats every yielding

Hw7-2.JPG

Now to get the original signal back all we need to do is us a filter to eliminate everything we don't want. I this case depending on what we want we can either take the centered frequency which is usually done in a receiver since a broad casted signal is usually broken up into a positive and negative component as seen in the original figure or we can just take the broken apart signal that we started with as seen below

Hw7-3.JPG

Notice if we couldn't get the original signal after sampling because the signals would overlap as seen below


Hw7-4.JPG

Now that we can see that the original signal is recoverable lets look at x(t) in terms of x(nt)