Quadrature sampling waveform plot - HW10: Difference between revisions
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Running the MATLAB script above gives us the following plot.<br> |
Running the MATLAB script above gives us the following plot.<br> |
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[[Image:Quadrature sampling.jpg]] |
[[Image:Quadrature sampling.jpg]]<br> |
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Summing over a smaller range of <math> n \!</math> would look like the following.<br> |
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<pre> |
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clear all; |
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close all; |
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sum = 0; |
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T = 1; |
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t = -T:0.001:T; |
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N = 100; |
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for n = 1:N; |
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if n==0 |
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h = 0; |
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else |
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h = 2/T; |
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end |
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sum = sum+h*sin(2*pi*n*t/T); |
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end |
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plot(t,sum) |
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title('Quadrature Sampling Waveform') |
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xlabel('time(T)') |
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ylabel('Sampling Waveform') |
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</pre><br> |
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[[Image:Quadrature sampling2.jpg]] |
Latest revision as of 23:31, 1 December 2009
Max Woesner
Homework #10 - Quadrature sampling waveform plot
Problem Statement
Plot
Solution
While we can't sum to infinity in the computer, we can get a close approximation summing over a large enough range of
I found summing over was about the most the computer could handle reasonably.
The following script was written in MATLAB to produce the desired plot.
clear all; close all; sum = 0; T = 1; t = -T:0.0001:T; N = 1000; for n = 1:N; if n==0 h = 0; else h = 2/T; end sum = sum+h*sin(2*pi*n*t/T); end plot(t,sum) title('Quadrature Sampling Waveform') xlabel('time(T)') ylabel('Sampling Waveform')
Running the MATLAB script above gives us the following plot.
Summing over a smaller range of would look like the following.
clear all; close all; sum = 0; T = 1; t = -T:0.001:T; N = 100; for n = 1:N; if n==0 h = 0; else h = 2/T; end sum = sum+h*sin(2*pi*n*t/T); end plot(t,sum) title('Quadrature Sampling Waveform') xlabel('time(T)') ylabel('Sampling Waveform')