Laplace Transform: Difference between revisions

Revision as of 17:27, 11 January 2010

F(s)={\mathcal {L}}\left\{1\right\}=\int _{0}^{\infty }e^{-st}\,dt=

{\frac {1}{s}}

F(s)={\mathcal {L}}\left\{t^{2}\right\}=\int _{0}^{\infty }e^{-st}t^{2}\,dt=

{\frac {n!}{s^{n+1}}}

@@ Line 1: / Line 1: @@
 :<math>F(s) = \mathcal{L} \left\{1\right\}=\int_0^{\infty} e^{-st} \,dt = </math> <math> \frac {1}{s}</math>
+:<math>F(s) = \mathcal{L} \left\{t^2\right\}=\int_0^{\infty} e^{-st} t^2 \,dt = </math> <math> \frac {n!}{s^{n+1}}</math>
-     Normal   0               false   false   false      EN-US   X-NONE   X-NONE                                                     MicrosoftInternetExplorer4
-:<math>F(s) = \mathcal{L} \left\{t^2\right\}=\int_0^{\infty} e^{-st} \,dt = </math> <math> \frac {1}{s}</math>