Basic Op Amp circuits: Difference between revisions

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Revision as of 13:37, 12 January 2010

Buffer Amplifier

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Buffer Amplifier

Used to transfer voltage but not current to the following circuit. This amplifier can be used to negate the loading effects. No current flows through the amplifier, thus there is no voltage drop through the input resistor (going to the buffer amplifier).

Inverting Amplifier

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Inverting Amplifier

Uses negative feedback to invert and amplify voltage. Using nodal analysis at the negative terminal, the gain is found to be $- \frac{R_{2}}{R_{1}}$
$R_{b i a s} = \frac{R_{1} R_{2}}{R_{1} + R_{2}}$
To get rid of unwanted DC components, a capacitor can be added inbetween $R_{1}$ and $V_{i n}$ . In this case $R_{b i a s} = R_{2}$

Summing Amplifier

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Summing Amplifier

$V_{o} = - R_{f} (\frac{V_{3}}{R_{3}} + \frac{V_{2}}{R_{2}} + \frac{V_{1}}{R_{1}})$
If all resistances are equal, then the output voltage is the (negative) sum of the input voltages
$\frac{1}{R_{b i a s}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + \frac{1}{R_{f}}$

Noninverting Amplifier

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Noninverting Amplifier

$V_{o} = V_{i n} (1 + \frac{R_{2}}{R_{1}})$
$R_{b i a s} = \frac{R_{1} R_{2}}{R_{1} + R_{2}}$
$R_{b i a s}$ goes between the positive terminal and $V_{i n}$
To get rid of unwanted DC components, a capacitor can be added inbetween the positive terminal and $V_{i n}$ . The bias resistor has the same value, and is placed inbetween the positive input terminal and ground.

Differential Amplifier

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Differential Amplifier

$V_{o} = V_{2} \frac{(R_{1} + R_{f}) R_{g}}{(R_{2} + R_{g}) R_{1}} - V_{1} \frac{R_{f}}{R_{1}}$
If you let $R_{1} = R_{2}$ and $R_{g} = R_{f}$ then the equation simplifies to $V_{o} = \frac{R_{f}}{R_{1}} (V_{2} - V_{1})$

@@ Line 14: / Line 14: @@
 [[Image:InvertingAmplifier.png|thumb|300px|Inverting Amplifier]]
 *Uses negative feedback to invert and amplify voltage. Using nodal analysis at the negative terminal, the gain is found to be <math>-\frac{R_2}{R_1}</math>
+*<math>R_{bias}=\frac{R_1R_2}{R_1+R_2}</math>
-<br>
+*To get rid of unwanted DC components, a capacitor can be added inbetween <math>R_1\,</math> and <math>V_{in}\,</math>. In this case <math>R_{bias}=R_2\,</math>
-<br>
-<br>
 <br>
 <br>
@@ Line 23: / Line 21: @@
 <br>
 <br>
 ==Summing Amplifier==
 [[Image:Summing_Amplifier.PNG‎|thumb|300px|Summing Amplifier]]
 *<math>V_o=-R_f \left( \frac{V_3}{R_3}+\frac{V_2}{R_2}+\frac{V_1}{R_1}\right)</math>
 *If all resistances are equal, then the output voltage is the (negative) sum of the input voltages
+*<math>\frac{1}{R_{bias}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\frac{1}{R_f}</math>
-<br>
-<br>
-<br>
 <br>
 <br>
@@ Line 43: / Line 40: @@
 [[Image:Noninverting_Amplifier.PNG‎|thumb|300px|Noninverting Amplifier]]
 *<math>V_o=V_{in} \left(1+\frac{R_2}{R_1}\right)</math>
+*<math>R_{bias}=\frac{R_1R_2}{R_1+R_2}</math>
+*<math>R_{bias}\,</math> goes between the positive terminal and <math>V_{in}\,</math>
+*To get rid of unwanted DC components, a capacitor can be added inbetween the positive terminal and <math>V_{in}\,</math>. The bias resistor has the same value, and is placed inbetween the positive input terminal and ground.
 <br>
@@ Line 51: / Line 51: @@
 <br>
 <br>
 ==Differential Amplifier==
 [[Image:Differential_Amplifier_2.PNG‎|thumb|300px|Differential Amplifier ]]
 *<math>V_o=V_2\frac{(R_1+R_f)R_g}{(R_2+R_g)R_1}-V_1\frac{R_f}{R_1}</math>
 *If you let <math>R_1=R_2\,</math> and <math>R_g=R_f\,</math> then the equation simplifies to <math>V_o=\frac{R_f}{R_1}(V_2-V_1)</math>

Basic Op Amp circuits: Difference between revisions

Revision as of 13:37, 12 January 2010

Contents

Buffer Amplifier

Inverting Amplifier

Summing Amplifier

Noninverting Amplifier

Differential Amplifier

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Basic Op Amp circuits: Difference between revisions

Revision as of 13:37, 12 January 2010

Buffer Amplifier

Inverting Amplifier

Summing Amplifier

Noninverting Amplifier

Differential Amplifier

Navigation menu

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