Example: Magnetic Field: Difference between revisions

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And we know the necessary Force to hold up the bar without the supports would be equal to the weight of the bar multiplied by the gravitational force.
And we know the necessary Force to hold up the bar without the supports would be equal to the weight of the bar multiplied by the gravitational force.
<!-- We also know that the force vector will be in the <math>\hat k</math> direction. -->
We also know that the force vector will be in the <math>\hat k</math> direction, and B is in the <math>\hat i</math> direction. So using the fact that <math>\hat k=-\hat j\times \hat i</math> We can conclude that the current is in the <math>-\hat j</math> direction, and flows to the left.



<math>\vec F_{\text{needed}}={\text{mass}}\times {\text{gravity}}</math>
<math>\vec F_{\text{needed}}={\text{mass}}\times {\text{gravity}}</math>
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<math>4.905=I * 1.2* 0.9 ~~(T*m/N) ~~ \to I=4.905/(1.2*0.9)=4.5417 ~~A</math>
<math>4.905=I * 1.2* 0.9 ~~(T*m/N) ~~ \to I=4.905/(1.2*0.9)=4.5417 ~~A</math>


In conclusion we would need 4.54 Amps of current to suspend the bar in the magnetic field.
In conclusion we would need 4.54 Amps of current flowing to the left to suspend the bar in the magnetic field.

Revision as of 15:41, 25 January 2010

Problem

A Metal Rod with length 1.2 m and mass 500 g is suspended in a magnetic field of 0.9 T. Determine the current needed suspend the rod without supports.

Figure will be shown here


Solution

Ampere's Force Law

For our problem we have

And we know the necessary Force to hold up the bar without the supports would be equal to the weight of the bar multiplied by the gravitational force. We also know that the force vector will be in the direction, and B is in the direction. So using the fact that We can conclude that the current is in the direction, and flows to the left.


Substituting into Ampere's Law we are left with

Integrating from l=0 to l=1.2 m gives us

In conclusion we would need 4.54 Amps of current flowing to the left to suspend the bar in the magnetic field.