The Class Notes: Difference between revisions

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<math>\oint \vec E d \vec \ell = \frac {-d}{dt} \int \vec B d \vec s \quad Faraday's\ Law</math>
<math>\oint \vec E d \vec \ell = \frac {-d}{dt} \int \vec B d \vec s \quad Faraday's\ Law</math>
hmm check these
<math> \vec E = \frac {J}{\sigma} </math>
<math> \lambda = L i</math>
e is voltage
<math> e = \frac {d \lambda}{dt} = L \frac{di}{dt}</math>

Revision as of 17:05, 25 January 2010

Notes for reviewer Be sure all 'l' have been replaced with

4 jan 2010

LimitA:

X0=1βXsV0=R1+R2R1Vin

Xi=0

Picture drawn by Kirk Betz based on drawing by Dr. Frohnes, lecture Jan. 4, 2010

Vin=V0(R1R1+R2).


V0=1(R1R1+R2)Vin

Magnetic Circuits

jan 6 2010

F=qv×B

dF=Id×B

=H1+H2

V=R1I+R2I

Picture drawn by Kirk Betz based on drawing by Dr. Frohnes, lecture Jan. 6, 2010

Magnetic Equations

Hd=

Hd=Ni=nH+Ni=0

Bds=0

Bds=ϕBAreaMagneticFlux

Reluctanceϕ=Niϕ

B=μHAssumesLinearity

μA

Picture drawn by Kirk Betz based on drawing by Dr. Frohnes, lecture Jan. 6, 2010

Pictures drawn by Kirk Betz based on drawing by Dr. Frohnes, lecture Jan. 6, 2010

Magnetic Circuits Examples

What about chancing currents, etc.?

Picture drawn by Kirk Betz based on drawing by Dr. Frohnes, lecture Jan. 8, 2010

Hd=Ni

Case i)

μ=104μ0inthecore Something about this part doesn't seem right.

FindBinthegap.

Graph and picture 6

H=NI, IH

NI=V

=μAR=σA

ϕ=BAI=JA

Rc=1μA

Rg=gμ0(A+g)2


ϕ=B(A+g)2=NIRg+Rc

BgNI(Rg+Rc)(A+g)2

Magnetic Circuits Continued

jan 11, 2010

some random graph here, can't really read it.

Case ii) Include non-linearity & find B in the Gap

Hd=NI=H1+Hg=H(1+g)

ϕ=Bds=BA

picture 7 goes here

ϕ=NIH1Rg=1Rg(H1)+NIRg not sure about the -1 here

What energy is list in the hysteresis loop?

P=vi

W=Pdt

Ed=ddtBdsFaradaysLaw

hmm check these

E=Jσ

λ=Li

e is voltage

e=dλdt=Ldidt