Integrator Amplifier: Difference between revisions
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=Amplifiers= |
=Amplifiers= |
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===Integrator === |
===Integrator === |
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[[Image:Integrator_ben.jpg|200px|thumb|right|Graph of a typical Integrator Amp circuit (drawing redrawn by Ben Henry)]] |
[[Image:Integrator_ben.jpg|200px|thumb|right|Graph of a typical Integrator Amp circuit (drawing redrawn by Ben Henry)]] |
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The circuit at right integrates the input voltage <math>V_{in}</math> by using an |
The circuit at right integrates the input voltage <math>V_{in}</math> by using an amplifier. |
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<math>V_{out} = \frac{-1}{R_{1}*C}\int V_{in} dt |
<math>V_{out} = \frac{-1}{R_{1}*C}\int V_{in} dt |
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</math> |
</math> |
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"<math>R_{2}</math> ; Provides negative feedback for low output impedance needs. But it also distorts the output."<sup>1</sup> |
"<math>R_{2}</math> ; Provides negative feedback for low output impedance needs. But it also distorts the output."<ref><sup>Quick Study "Electronics 1, Part 2"</sup></ref> |
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The use of an |
The use of an integrator circuit is the opposite of a differentiator circuit. In other words, If you have a triangle wave input and you differentiate it you will get a square wave output. If you run the square wave as the input to an integrator circuit you will end up with the triangle wave for the output<ref><sup>Scherz, P: ''Practical Electronics for Inventors 2nd ed'', page 545. </sup></ref>. |
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The |
The resistor (<math>R_{2}</math>) is used to provide feedback<ref><sup>[[Feedback_in_Amplifiers]]</sup></ref>. of the output DC voltage. Without this, circuit wouldn't perform as calculated because of the un-ideal conditions of real life. |
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==Contributers== |
==Contributers== |
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--[[User:Benjamin.henry|Benjamin.henry]] 23:15, 10 January 2010 (UTC) |
--[[User:Benjamin.henry|Benjamin.henry]] 23:15, 10 January 2010 (UTC) |
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==Reviewers== |
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[[Greg Fong]] |
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[[Shepherd,Victor]] |
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==Sources== |
==Sources== |
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<references/> |
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<sup>1</sup> Quick Study "Electronics 1, Part 2" |
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<sup>2</sup> [[Feedback_in_Amplifiers]] |
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<sup>3</sup> Practical Electronics for Inventors (p545, 2nd edition) |
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Latest revision as of 09:39, 28 January 2010
Amplifiers
Integrator
The circuit at right integrates the input voltage by using an amplifier.
" ; Provides negative feedback for low output impedance needs. But it also distorts the output."<ref>Quick Study "Electronics 1, Part 2"</ref>
The use of an integrator circuit is the opposite of a differentiator circuit. In other words, If you have a triangle wave input and you differentiate it you will get a square wave output. If you run the square wave as the input to an integrator circuit you will end up with the triangle wave for the output<ref>Scherz, P: Practical Electronics for Inventors 2nd ed, page 545. </ref>. The resistor () is used to provide feedback<ref>Feedback_in_Amplifiers</ref>. of the output DC voltage. Without this, circuit wouldn't perform as calculated because of the un-ideal conditions of real life.
Contributers
--Benjamin.henry 23:15, 10 January 2010 (UTC)
Reviewers
Sources
<references/>