Problem Set 1: Difference between revisions

Revision as of 08:46, 5 February 2010

Problem

Find the core inductance and resitence of a transformer using measurmnets Voc=5V, Ioc=3A, and Poc =10W.

Solution

Power is found only through resister

$Poc=Voc^{2}/R$

Both Poc and Voc are giving so solve for R

$R=Voc^{2}/Poc=5V/10W=2.5Ohms$

To calclate the core inductance we will use the formular for appearent power.

$S^{2}=P^{2}+Q^{2}$

$S^{2}=|Voc*Ioc^{*}|^{2}$

Subtituting in values aand solving gives $S^{2}=(5V*3A)^{2}=225(VA)^{2}$

$Q={\sqrt {P^{2}-Q^{2}}}$

${Z_{th}}={\frac {{\frac {N_{1}}{N_{2}}}{e_{2}}}{{\frac {N_{2}}{N_{1}}}{i_{2}}}}$

@@ Line 3: / Line 3: @@
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-Find the core inductance and resitence of a transformer using measurmnets Voc=5V, Ioc=3V, and Poc =10V.
+Find the core inductance and resitence of a transformer using measurmnets Voc=5V, Ioc=3A, and Poc =10W.
 ----
@@ Line 11: / Line 11: @@
 Power is found only through resister
-<math>P= </math>
+<math>Poc= Voc^{2}/R</math>
+Both Poc and Voc are giving so solve for R
+<math>R=Voc^{2}/Poc=5V/10W=2.5 Ohms</math>
+To calclate the core inductance we will use the formular for appearent power.
+<math>S^{2}=P^{2}+Q^{2}</math>
+<math>S^{2}=|Voc*Ioc^{*}|^{2}</math>
+Subtituting in values  aand solving gives
+<math>S^{2}=(5V*3A)^{2}=225(VA)^{2}</math>
+<math>Q=\sqrt{P^{2}-Q^{2}}</math>
+<math>{Z_{th}}=\frac{\frac{N_{1}}{N_{2}}{e_{2}}}{\frac{N_{2}}{N_{1}}{i_{2}}}</math>