Chapter 4 problems: Difference between revisions
Jump to navigation
Jump to search
(→4.20) |
(→4.20) |
||
Line 13: | Line 13: | ||
| .2 || .62 || 10 |
| .2 || .62 || 10 |
||
|} |
|} |
||
:*Writing a loop equation for the output: <math>-V_{CC}+R_CI_C+V_{CE}=0</math> |
|||
===4.34=== |
===4.34=== |
Revision as of 10:45, 5 March 2010
4.20
- We want to establish a DC operating point for the BJT. Writing a loop equation gives us -VBB-Vin(t)+iBRB+vBE=0. To form a load line, we will let vin(t)=0 & iB=0. Thus vBE=VBB+vin(t) and iB(t)=(VBB+vin(t))/RB
- for the minimum, Q-point and maximum values.
-.2 .45 2 0 .58 5 .2 .62 10
- Writing a loop equation for the output: