Christman GeneralizedReceiver

How It Works: Generalized Receiver

The process of transmitting data, $m(t)$, via a wireless signal, $v(t)$, is shown below:

As can be seen from the figure above, in order to transmit $m(t)$, one must first process the data using a baseband processor (usually accomplished with software). As a result of this process the original data will be split into two signals, $x(t)$ and $y(t)$, and shifted to a frequency $f_c$ (and $-f_c$ because of the notion of a complex conjugate). Note that the original wireless communication data that you want to send is in the form known as baseband, which consists of frequencies near D.C. (or $f_c=0$). When you actually send the communication data, however, you want to send it via much higher frequency (one which is inaudible to humans) and this creates a bandpass signal. This concept is illustrated below:

How is the data split and shifted you ask? Mathematically speaking, in the world of "Communication Systems" a signal to be transmitted can be written as

$v(t)=Re[g(t)\cdot e^{j({\omega }_{c}t)}]$,

where $g(t)=x(t)+jy(t)$ is the signal to be sent and $e^{j{\omega }_{c}t}=\cos ({\omega }_{c}t)+j\sin ({\omega }_{c}t)$ (Euler's identity) shifts the signal in the frequency domain by ${\omega }_c=2\pi f_c$.
The above formula can then be rewritten to obtain the following relationship:

$v(t)=Re[g(t)\cdot e^{j{\omega }_{c}t}]=Re[(x(t)+jy(t))\cdot (\cos ({\omega }_{c}t)+j\sin ({\omega }_{c}t))]=x(t)\cos ({\omega }_{c}t)-y(t)\sin ({\omega }_{c}t)$.

As you can also from the above relationship, in order to obtain the appropriate output signal $v(t)$ one must multiply $x(t)$ by a cosine function and $y(t)$ by a negative sine function and then sum the results (this is illustrated in the figure above). In simplified terms and details, this is essentially how the data $m(t)$ is transmitted.

Receiving the original data from a wireless signal is very similar to that of transmitting the data (as described before). The process of receiving data, $m(t)$, via a wireless signal, $v(t)$, is shown below:

In short, the data that we are interested in ($m(t)$) is embedded within the carrying signal ($v(t)$) which is at a frequency inaudible to human ears. Thus, in order to get the original communication data it is necessary to somehow bring the bandpass signal back down to its original baseband form -- and this is what the second quarter of electronics is all about. If you have not already discovered, to recover the original data $x(t)$ and $y(t)$ from the signal signal $v(t)$ we must perform a task known as "mixing" and then run the results through low pass filters. Simply put, we need to multiply $v(t)$ by $\cos ({\omega }_{c}t)$ and $-\sin ({\omega }_{c}t)$. To see this mathematically, recall that $v(t)=x(t)\cos ({\omega }_{c}t)-y(t)\sin ({\omega }_{c}t)$. Therefore,

$\cos ({\omega }_{c}t)\cdot v(t)=cos({\omega }_{c}t)\cdot [x(t)\cos ({\omega }_{c}t)-y(t)\sin ({\omega }_{c}t)]=x(t){\cos }^{}({\omega }_{c}t)-y(t)\cos ({\omega }_{c}t)\sin ({\omega }_{c}t)$

But when $\cos ({\omega }_{c}t)\sin ({\omega }_{c}t)$ is ran through a low pass filter it is filtered out, whereas ${\cos }^2({\omega }_{c}t)$ is not; therefore, we are left with $x(t)$ as desired! (Similarly, $y(t)$ can be obtained.)