HW 6: Difference between revisions

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Created page with '(Ben Henry) ; Convolution : If <math>h(x)=\left(f*g\right)(x)</math>, becomes   <math> \hat{h}(\xi)=\hat{f}(\xi)\cdot \hat{g}(\xi).</math>'
 
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Latest revision as of 09:58, 15 October 2010

(Ben Henry)

Convolution
If h(x)=(f*g)(x), becomes   h^(ξ)=f^(ξ)⋅g^(ξ).
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