Matthew's Asgn: Difference between revisions

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<math>\ \dfrac{s}{(s^2+w^2)(R+Ls)} = \dfrac{A}{(s+jw)} + \dfrac{A*}{(s-jw)} + \dfrac{B}{(Ls+R)} \,\!</math>
<math>\ \dfrac{s}{(s^2+w^2)(R+Ls)} = \dfrac{A}{(s+jw)} + \dfrac{A*}{(s-jw)} + \dfrac{B}{(Ls+R)} \,\!</math>


<math>\ \dfrac{s/L}{(s^2+w^2)(R/L+s)} = \dfra{A(s+jw)(s+R/L)}{(s+R/L)(s^2+w^2)} + \dfrac{A*(s+jw)(s+R/L)}{(s^2+w^2)(s+R/L)} + dfrac{B(s^2+w^2)}{(s+R/L)(s^2+w^2)} \,\!</math>
<math>\ \dfrac{s/L}{(s^2+w^2)(R/L+s)} = \dfrac{A(s+jw)(s+R/L)}{(s+R/L)(s^2+w^2)} + \dfrac{A*(s+jw)(s+R/L)}{(s^2+w^2)(s+R/L)} + \dfrac{B(s^2+w^2)}{(s+R/L)(s^2+w^2)} \,\!</math>


<math>\ S/L = A((s-jw)(s+R/L)) + A*((s+jw)(s+R/L)) + B(s^2+w^2)
<math> \dfrac{S}{L} = A(s-jw)(s+R/L) + A*((s+jw)(s+R/L)) + B(s^2+w^2) \,\!</math>



= A(s^2-jws+R/Ls-jwR/L) + a*(s^2+jws+R/L+jwr/L) + B(s^2+w^2) \,\!</math>
<math> = A(s^2-jws+R/Ls-jwR/L) + a*(s^2+jws+R/L+jwr/L) + B(s^2+w^2) \,\!</math>

Revision as of 16:56, 1 November 2010

I decided that I would attempt to perform a simple analysis of a series RL circuit, which could then be used to do a more complex analysis on a basic transformer. I have always had interest in electronics, and transformers are key to basic electronics.

I decided that i would do the analysis of a RL circuit with the variables instead of given values.


Given:

V(t)=

V(s)=

I(0)=i

RLcircuit.jpg

The Laplace transform for an inductor:

=

The Laplace transform for a resistor:

=

Therefore the Resulting Equation for the system after applying the Laplace Transform:

A series of algebraic manipulations follows to come up with I(s):



We can then use partial fraction manipulation to expand the expression: