Signals and systems/GF Fourier: Difference between revisions
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==Fourier series== |
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The Fourier series is used to analyze arbitrary periodic functions by showing them as a composite of sines and cosines. |
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A function is considered periodic if <math> x(t) = x(t+T)\, </math> for <math> T \neq 0 </math>. |
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The exponential form of the Fourier series is defined as <math> x(t) = \sum_{n=-\infty}^\infty \alpha_n e^{{j2\pi nt}/T} \, </math> |
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==Determining the coefficient <math> \alpha_n \,</math> == |
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<math> x(t) = \sum_{n=-\infty}^\infty \alpha_n e^{{j2\pi nt}/T} \, </math> |
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*The definition of the Fourier series |
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<math> \int_{-T/2}^{T/2} x(t)\, dt = \sum_{n=-\infty}^\infty \alpha_n \int_{-T/2}^{T/2} e^{{j2\pi nt}/T} dt</math> |
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*Integrating both sides for one period. The range of integration is arbitrary, but using <math> \int_{-T/2}^{T/2} </math> scales nicely when extending the Fourier series to a non-periodic function |
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<math> \int_{-T/2}^{T/2} x(t) e^{{-j2\pi mt}/T} dt = \sum_{n=-\infty}^\infty \alpha_n \int_{-T/2}^{T/2} e^{{j2\pi nt}/T}e^{{-j2\pi mt}/T} dt = \sum_{n=-\infty}^\infty \alpha_n \int_{-T/2}^{T/2} e^{{j2\pi (n-m)t}/T} dt</math> |
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*Multiply by the complex conjugate |
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<math> \int_{-T/2}^{T/2} x(t) e^{{-j2\pi mt}/T} dt = \sum_{n=-\infty}^\infty \alpha_n \frac{Te^{{j2\pi (n-m)t}/T}}{{j2\pi (n-m)}} \bigg|_{-T/2}^{T/2} = \sum_{n=-\infty}^\infty \alpha_n T\delta_{n,m} = T\alpha_m</math> |
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*<math> \frac{Te^{{j2\pi (n-m)t}/T}}{{j2\pi (n-m)}} \bigg|_{-T/2}^{T/2} = T\frac{e^{j\pi(n-m)}-e^{-j\pi(n-m)}}{j2\pi(n-m)} = T \frac{\sin\pi(n-m)}{\pi(n-m)} = \begin{Bmatrix} T, n=m \\ 0, n\ne m \end{Bmatrix} = T\delta_{n,m}</math> |
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** Using L'Hopitals to evaluate the <math>\frac{T\cdot 0}{0}</math> case. Note that n & m are integers |
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<math> \alpha_m = \frac{1}{T}\int_{-T/2}^{T/2} x(t) e^{{-j2\pi mt}/T} dt </math> |
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==Linear Time Invariant Systems== |
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Must meet the following criteria |
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*Time independance |
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*Linearity |
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**Superposition (additivity) |
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**Scaling (homogeneity) |
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==The Dot Product, Complex Conjugates, and Orthogonality== |
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[[Image:300px-Scalarproduct.gif |thumb|300px|right]] |
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Geometrically, the dot product is a scalar projection of a onto b |
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*<math> \vec a \cdot \vec b = \left | a \right \vert \left | b \right \vert \cos \theta</math> |
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Arthimetically, multiply like terms and add |
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*<math> (3,2,1)\cdot(5,6,7)=3\cdot5^*+2\cdot6^*+1\cdot7^*</math> |
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Lets imagine that we are only have one dimension |
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*<math> (a+jb)\hat i \cdot (a+jb)\hat i \ne a^2+b^2 </math> |
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In order to get the real parts and imaginary parts to multiply as like terms, we need to take the complex conjugate of one of the terms |
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*<math> (a+jb)\hat i \cdot (a-jb)\hat i = a^2+b^2 </math> |
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To test for orthogonality, take the complex conjugate of one of the vectors and multiply. |
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*<math> \int_{-\infty}^{\infty} \phi_n (t) \phi_m^* (t) dt = 0</math> |
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==Changing Basis Functions== |
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We'd like to change from <math> \sum_{n=-\infty}^{\infty} \alpha_n e^{j2\pi nt/T} </math> to <math> \sum_{m=0}^{\infty} c_n \cos \left (\frac{2\pi mt}{T}+\Theta_m \right) </math> |
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<math> x(t) = \sum_{n=-\infty}^{\infty} \alpha_n e^{j2\pi nt/T} = \underbrace{ \sum_{n=-\infty}^{-1} \alpha_n e^{j2\pi nt/T} }_{n'=-n} + \alpha_0 + \sum_{n=1}^{\infty} \alpha_n e^{j2\pi nt/T}</math> |
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<math> = \underbrace{\sum_{n'=1}^{\infty} \alpha_n e^{j2\pi nt/T}}_{m=n'} + \alpha_0 + \underbrace{\sum_{n=1}^{\infty} \alpha_n e^{j2\pi nt/T}}_{m=n}</math> |
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<math> = \alpha_0 + \sum_{m=1}^{\infty} \left (\alpha_m e^{j2\pi mt/T} + \alpha_{-m} e^{-j2\pi mt/T}\right) </math> |
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If we assume <math> x(t) \in \Re \ \forall \ m</math>, then to make the imaginary parts cancel out |
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*<math> \alpha_{-m} = \alpha_m^* </math> |
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*<math> u + u^* = 2 \Re [u] </math> |
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*<math> \alpha_{m} = | \alpha_m |e^{j\theta m} \,</math> |
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==Identities== |
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<math>e^{j \theta} = \cos \theta + j \sin \theta \, </math> Euler's identity linking rectangular and polar coordinates |
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<math>\sin x = \frac{e^{jx}-e^{-jx}}{2j} \,</math> |
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<math>\cos x = \frac{e^{jx}+e^{-jx}}{2} \,</math> |
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<math> \left \langle \ Bra \mid Ket \ \right \rangle = Ket \cdot Bra </math> |
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<math> \alpha_{-m} = \alpha^* \,</math> |
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The dirac delta has an infinite height and an area of 1 |
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