Using the DFT: Difference between revisions

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This is what we get when we sample the signal at 3Hz
sampling <math>sin(2*pi*t)</math> and taking the DFT we get this graph:

[[Image:hw13_1.jpg]]


Taking the original signal <math>sin(2*pi*t)</math> and applying the DFT we get this graph:


[[Image:Signals-13.jpg]]
[[Image:Signals-13.jpg]]


Now taking the DFT of this sampled signal, we get a graph like this:

[[Image:hw13_2.jpg]]







Script for matlab:
Script for matlab:

clear all;
clear all;


t=0:.01:1;
t=0:.01:2;


T=0.20;
T=1/3;


ts=0:T:1;
ts=0:T:2;


f1=2;
f1=2;
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f2=1/0.125;
f2=1/0.125;


x = sin(2*pi*3*t); %this is the function
x = sin(2*pi*ts); %this is the function


plot(t,x); % plot the original signal
plot(ts,sin(2*pi*ts),'r-',t,sin(2*pi*t)); % plot the original signal and the signal sampled at 3Hz


X = fft(x); % take the DFT
X = fft(x); % take the DFT
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pause (2);
pause (2);


plot (t,X); %plot the DFT of the signal
plot (ts,X); %plot the DFT of the signal sampled at 3Hz

pause (4);

x=sin(2*pi*t);

plot(t,x);

pause(2);

X = fft(x);

plot(t,X); %plot the DFT of the original signal

Latest revision as of 10:18, 27 November 2007

This is what we get when we sample the signal at 3Hz

File:Hw13 1.jpg


Taking the original signal and applying the DFT we get this graph:

Signals-13.jpg


Now taking the DFT of this sampled signal, we get a graph like this:

File:Hw13 2.jpg



Script for matlab:

clear all;

t=0:.01:2;

T=1/3;

ts=0:T:2;

f1=2;

f2=1/0.125;

x = sin(2*pi*ts); %this is the function

plot(ts,sin(2*pi*ts),'r-',t,sin(2*pi*t)); % plot the original signal and the signal sampled at 3Hz

X = fft(x); % take the DFT

pause (2);

plot (ts,X); %plot the DFT of the signal sampled at 3Hz

pause (4);

x=sin(2*pi*t);

plot(t,x);

pause(2);

X = fft(x);

plot(t,X); %plot the DFT of the original signal