EMEC: Difference between revisions

Latest revision as of 19:10, 18 January 2010

$r_{m}=({\frac {1}{2}}){\frac {OD+ID}{2}}$

$l_{m}={2\pi r_{m}}=0.141\$

$H_{m}=({\frac {Ni}{l_{m}}})$

$H_{m}={\frac {20x2.5}{.141}}=354.6\ A/m)$

@@ Line 1: / Line 1: @@
 <math>r_m=(\frac{1}{2})\frac{OD + ID}{2}</math>
+<math> l_m = { 2 \pi r_m} = 0.141\ </math>
 <math>H_m=(\frac{Ni}{l_m})</math>
-<math>H_m=(\frac{20 x 2.5}{.141}= 354.6 A/m)</math>
+<math>H_m=\frac{20 x 2.5}{.141}= 354.6\ A /m)</math>