Problem Set 1: Difference between revisions

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'''Problem'''
'''PROBLEM'''


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'''Solution'''
'''SOLUTION'''


Power is stored in resistors because of their linear behavior.  
Power is stored in resistors because of their linear behavior.  
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Both Poc and Voc are giving so solve for R
Both Poc and Voc are giving so solve for R


<math>R=Voc^{2}/Poc=5V/10W=2.5 Ohms\!</math> Answer
<math>R=Voc^{2}/Poc=5V/10W=2.5 Ohms\!</math> ''''' Answer'''''


Apparent power relation to voltage and current is  
Apparent power relation to voltage and current is  
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<math>S^{2}=P^{2}+Q^{2}\!</math>
<math>S^{2}=P^{2}+Q^{2}\!</math>


Use the apparent power and the real power to find the reactive power
Solve the above equation for reactive power using the values of apparent and real power.


<math>Q=\sqrt{S^{2}-P^{2}}= \sqrt{225^{2}-10^{2}}= 224.8VAr\!</math> Answer
<math>Q=\sqrt{S^{2}-P^{2}}= \sqrt{225^{2}-10^{2}}= 224.8VAr\!</math>  


Reactive power is stored in non-linear impedance represented as X. In this case X is inductance.
Reactive power is stored in non-linear impedance represented as X. In this case X is inductance.
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<math>Q=Voc^{2}/X\!</math>
<math>Q=Voc^{2}/X\!</math>


<math>X=Voc^{2}/Q=5V^{2}/224.8VAr=0.11H \!</math>
<math>X=Voc^{2}/Q=5V^{2}/224.8VAr=0.11H \!</math> '''''Answer'''''

Latest revision as of 23:43, 8 February 2010

PROBLEM


Find the core inductance and resistance of a transformer using measurements Voc=5V, Ioc=3A, and Poc =10W.


SOLUTION

Power is stored in resistors because of their linear behavior.

Poc=Voc2/R

Both Poc and Voc are giving so solve for R

R=Voc2/Poc=5V/10W=2.5Ohms Answer

Apparent power relation to voltage and current is

S2=|Voc*Ioc*|2

The magnitude for current and voltage are given in the problem statement. Subtitute in known values and solve.

S2=(5V*3A)2=225(VA)2

Apparent power S is complex. It has a real part P, real power, and an imaginary part Q, reactive power.

S=P+iQ

Apparent power in the imaginary and real coordinate system is the hypotenuse of real and reactive power and can be expressed using the equation of a circle.

S2=P2+Q2

Solve the above equation for reactive power using the values of apparent and real power.

Q=S2P2=2252102=224.8VAr

Reactive power is stored in non-linear impedance represented as X. In this case X is inductance.

Q=Voc2/X

X=Voc2/Q=5V2/224.8VAr=0.11H Answer