Fourier transform: Difference between revisions

From Class Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Line 9: Line 9:
Suppose that we have some function, say <math> \beta (t) </math>, that is nonperiodic and finite in duration.<br>
Suppose that we have some function, say <math> \beta (t) </math>, that is nonperiodic and finite in duration.<br>
This means that <math> \beta(t)=0 </math> for some <math> T_\alpha < \left | t \right | </math>
This means that <math> \beta(t)=0 </math> for some <math> T_\alpha < \left | t \right | </math>
<br><br>
Now let's make a periodic function <math> \gamma(t) </math> by repeating <math> \beta(t) </math> with a fundamental period <math> T_\zeta </math>.
<br>
The Fourier Series representation of <math> \gamma(t) </math> is
<br>
<math> \gamma(t)=\sum_{k=-\infty}^\infty \alpha_k e^{j2\pi fkt} </math> where <math> f={1\over T_\alpha}
</math> <br>and <math> \alpha_k={1\over T_\alpha}\int_{-{T_\alpha\over 2}}^{{T_\alpha\over 2}} \gamma(t) e^{-j2\pi kt}\,dt</math>

Revision as of 08:44, 8 December 2004

An initially identity that is useful:

Suppose that we have some function, say , that is nonperiodic and finite in duration.
This means that for some

Now let's make a periodic function by repeating with a fundamental period .
The Fourier Series representation of is
where
and