Homework: Difference between revisions

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<math>  
<math>  
\left \langle \phi_k(t) \| \phi_l(t) \right \rangle=\int_{-\infty}^{\infty} \phi_k(t)* \phi_l(t)\,dt
\left \langle \phi_k(t) \vert \phi_l(t) \right \rangle=\int_{-\infty}^{\infty} \phi_k(t)^{*} \phi_l(t)\,dt
</math>
<br>
<math>
x(t)=\sum_{k=-\infty}^{\infty} x(kT)\phi_k(t)
</math>
</math>

Revision as of 09:10, 10 December 2004

Homework #9

Problem Statement:
Show that, for a bandwidth limited signal (x(t) with fmax<12T)
k=|x(kT)|2=c|x(t)|2dt
And find c.

Equations:
ϕk(t)|ϕl(t)=ϕk(t)*ϕl(t)dt
x(t)=k=x(kT)ϕk(t)