Homework Four: Difference between revisions
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<math> \mathcal{F}[10^{t}g(t)e^{j2 \pi ft_0}] = \int_{-\infty}^{\infty}10^{t}g(t)e^{j2 \pi ft_0}e^{-j2 \pi ft}\,dt = \int_{-\infty}^{\infty}10^{t}g(t)e^{j2 \pi f(t_{0}-t)}\,dt</math> |
<math> \mathcal{F}[10^{t}g(t)e^{j2 \pi ft_0}] = \int_{-\infty}^{\infty}10^{t}g(t)e^{j2 \pi ft_0}e^{-j2 \pi ft}\,dt = \int_{-\infty}^{\infty}10^{t}g(t)e^{j2 \pi f(t_{0}-t)}\,dt</math> |
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But recall that <math>e^{j2 \pi f(t_{0}-t)} \equiv \delta (t_{0}-t) \mbox{ or } \delta (t-t_{0})</math> |
But recall that <math>\int_{-\infty}^{\infty}e^{j2 \pi f(t_{0}-t)}df \equiv \delta (t_{0}-t) \mbox{ or } \delta (t-t_{0})</math> |
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The following needs to be fixed, because the previous thing (just above this) which we just fixed wasn't an identity. Hint: <math>10^{t}</math> is related to <math>e^{t}</math> |
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Because of this definition, our problem has now been simplified significantly: <br/> |
Because of this definition, our problem has now been simplified significantly: <br/> |
Revision as of 14:10, 19 October 2009
Find
To begin, we know that
But recall that
The following needs to be fixed, because the previous thing (just above this) which we just fixed wasn't an identity. Hint: is related to
Because of this definition, our problem has now been simplified significantly:
Therefore,