Homework Four: Difference between revisions

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<math> \mathcal{F}[10^{t}g(t)e^{j2 \pi ft_0}] = \int_{-\infty}^{\infty}10^{t}g(t)e^{j2 \pi ft_0}e^{-j2 \pi ft}\,dt = \int_{-\infty}^{\infty}10^{t}g(t)e^{j2 \pi f(t_{0}-t)}\,dt</math>
<math> \mathcal{F}[10^{t}g(t)e^{j2 \pi ft_0}] = \int_{-\infty}^{\infty}10^{t}g(t)e^{j2 \pi ft_0}e^{-j2 \pi ft}\,dt = \int_{-\infty}^{\infty}10^{t}g(t)e^{j2 \pi f(t_{0}-t)}\,dt</math>


But recall that <math>e^{j2 \pi f(t_{0}-t)} \equiv \delta (t_{0}-t) \mbox{ or } \delta (t-t_{0})</math>
But recall that <math>\int_{-\infty}^{\infty}e^{j2 \pi f(t_{0}-t)}df \equiv \delta (t_{0}-t) \mbox{ or } \delta (t-t_{0})</math>


The following needs to be fixed, because the previous thing (just above this) which we just fixed wasn't an identity. Hint: <math>10^{t}</math> is related to <math>e^{t}</math>


Because of this definition, our problem has now been simplified significantly: <br/>
Because of this definition, our problem has now been simplified significantly: <br/>

Revision as of 14:10, 19 October 2009

Fourier Transform Properties


Find

To begin, we know that

But recall that

The following needs to be fixed, because the previous thing (just above this) which we just fixed wasn't an identity. Hint: is related to

Because of this definition, our problem has now been simplified significantly:


Therefore,