Laplace transforms:DC Motor circuit: Difference between revisions

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=== Solution ===
=== Solution ===
The torque is proportional to the armature current.
<math>T(t) = k i(t)</math>
Similarly, relating mechanical (''T(t)&omega;(t)'') and electrical (''v<sub>m</sub>(t)i(t)'') power, the conservation of energy requires the same proportionality between the voltage across the motor (''v<sub>m</sub>(t)'') and the angular velocity (''&omega;(t)'').
<math>v_m(t) = k \omega(t)</math>
We want to find the Laplace transfer function of the motor.
<math>\Omega(s) = \mathcal{L}[\omega(t)]/v_s(s)</math>

Revision as of 19:56, 20 October 2009

Problem

Find the steady state current i(t) through a DC motor represented by a series R-L-Motor circuit. The resistance (R) is from the armature winding. The inductance (L) is the equivalent inductance of the wire coil (which turns by current flowing through the coil in a permanent magnetic field). The motor has input current i(t) and output angular velocity ω(t).

Solution

The torque is proportional to the armature current.

T(t)=ki(t)

Similarly, relating mechanical (T(t)ω(t)) and electrical (vm(t)i(t)) power, the conservation of energy requires the same proportionality between the voltage across the motor (vm(t)) and the angular velocity (ω(t)).

vm(t)=kω(t)

We want to find the Laplace transfer function of the motor.

Ω(s)=[ω(t)]/vs(s)