Laplace transforms: Critically Damped Motion: Difference between revisions

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<math>\frac{8}{32}=frac(1)(4)</math>
<math>\frac{8}{32}=1/4

Revision as of 17:03, 22 October 2009

Using the Laplace Transform to solve a spring mass system that is critically damped

Problem Statement

An 8 pound weight is attached to a spring with a spring constant k of 4 lb/ft. The spring is stretched 2 ft and rests at its equilibrium position. It is then released from rest with an initial upward velocity of 3 ft/s. The system contains a damping force of 2 times the initial velocity.

Solution

Things we know

<math>\frac{8}{32}=1/4

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