Coupled Oscillator: Jonathan Schreven: Difference between revisions
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Using F=ma we can then find our equations of equilibrium. |
Using F=ma we can then find our equations of equilibrium. |
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:<math>F=ma</math> |
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:<math> |
:<math>\begin{alignat}{3} |
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F & = ma \\ |
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:<math>-k_{1}x_{1}-k-{2}(x_1x_2)=m\ddot{x}</math> |
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F & = m\ddot{x} \\ |
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-k_{1}x_{1}-k_{2}(x_1x_2) & = m_1\ddot{x_1} \\ |
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-{k_1x_1 \over {m_1}}-{k_2(x_1-x_2) \over {m_1}} & = m_1\ddot{x_1} \\ |
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-{k_1x_1 \over {m_1}}-{k_2(x_1-x_2) \over {m_1}} & = \ddot{x_1} \\ |
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-{k_1+k_2 \over {m_1}}x_1+{k_2 \over {m_1}}x_2 & = \ddot{x_1} \\ |
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\end{alignat}</math> |
Revision as of 17:27, 9 December 2009
Coupled Oscillator System
In this problem I would like to explore the solution of a double spring/mass system under the assumption that the blocks are resting on a smooth surface. Our system might look something like this.
Using F=ma we can then find our equations of equilibrium.