Coupled Oscillator: horizontal Mass-Spring: Difference between revisions

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=
=
\begin{bmatrix}
\begin{bmatrix}
0 & 1 & 0 & 0 \\
0 & 0 & 0 & 0 \\
-4.5 & 0 & 2 & 0 \\
0 & 0 & 0 & 0 \\
0 & 0 & 0 & 1 \\
0 & 0 & 0 & 0 \\
4 & 0 & -4 & 0
0 & 0 & 0 & 0
\end{bmatrix}
\end{bmatrix}


Line 150: Line 150:


From this we get
From this we get
:<math>\lambda_1=2.6626i\,</math>
:<math>\lambda_1=\,</math>
:<math>\lambda_2=-2.6626i\,</math>
:<math>\lambda_2=\,</math>
:<math>\lambda_3=1.18766i\,</math>
:<math>\lambda_3=\,</math>
:<math>\lambda_4=-1.18766i\,</math>
:<math>\lambda_4=\,</math>

Revision as of 13:53, 10 December 2009

Problem Statement

Write up on the Wiki a solution of a coupled oscillator problem like the coupled pendulum. Use State Space methods. Describe the eigenmodes and eigenvectors of the system.

 Horizontal spring.jpg

Initial Conditions:

Equations for M_1

Equations for M_2

Additional Equations

State Equations

=

With the numbers...


=

Eigen Values

Once you have your equations of equilibrium in matrix form you can plug them into a calculator or a computer program that will give you the eigen values automatically. This saves you a lot of hand work. Here's what you should come up with for this particular problem given these initial conditions.

Given

We now have

From this we get