Example problems of magnetic circuits: Difference between revisions
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Solution: | Solution: | ||
First we need to find the permeability of copper <math> \mu </math> given by the equation <br> <math> \mu = \mu_0 (1 + \chi_m)</math> <br> <br> | First we need to find the permeability of copper <math> \mu </math> given by the equation <br> <math> \mu = \mu_0 (1 + \chi_m)</math> <br> <br> | ||
Which yeilds <math> \mu = 4*\pi*10^{-7}(1+-9.7x10^{-6}) = 1.2566x10^{-6} | Which yeilds <math> \mu = 4*\pi*10^{-7}(1+-9.7x10^{-6}) = 1.2566x10^{-6} </math> <br><br> | ||
Now with this, the length and cross sectional area of the core we can solve for reluctance <math> R_c </math> by: <br> | |||
<math> R_c = \frac{L}{\mu A} = \frac{1}{1.2566x10^{-6}*.1} = 7.96x10^{6} | |||
Revision as of 18:48, 10 January 2010
Given:
A copper core with susceptibility
length of core L = 1 m
Gap length g = .01 m
cross sectional area A = .1 m
current I = 10A
N = 5 turns
Find: B
Solution:
First we need to find the permeability of copper given by the equation
Which yeilds
Now with this, the length and cross sectional area of the core we can solve for reluctance by:
<math> R_c = \frac{L}{\mu A} = \frac{1}{1.2566x10^{-6}*.1} = 7.96x10^{6}