Laplace Transform: Difference between revisions

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:<math>F(s) = \mathcal{L} \left\{e^{at} t^n\right\}=\int_0^{\infty} e^{-st} e^{at} t^n \,dt = </math> <math> \frac {n!} {(s-a)^{n+1}} \mbox{ for}~n\ \mbox{= 1,2,...}</math>
:<math>F(s) = \mathcal{L} \left\{e^{at} t^n\right\}=\int_0^{\infty} e^{-st} e^{at} t^n \,dt = </math> <math> \frac {n!} {(s-a)^{n+1}} \mbox{ for}~n\ \mbox{= 1,2,...}</math>
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:<math>F(s) = \mathcal{L} \left\{te^{-t}\right\}=\int_0^{\infty} e^{-st} te^{-t} \,dt = </math> <math> \frac {1} {(s+1)^2} </math>
:<math>F(s) = \mathcal{L} \left\{te^{-t}\right\}=\int_0^{\infty} e^{-st} te^{-t} \,dt = </math> <math> \frac {1} {(s+1)^2} </math>

Revision as of 19:37, 11 January 2010

Standard Form:

F(s)={f(t)}=0estf(t)dt

Sample Functions:

F(s)={1}=0estdt= 1s
F(s)={tn}=0esttndt= n!sn+1
F(s)={eat}=0esteatdt= 1sa
F(s)={sin(ωt)}=0estsin(ωt)dt= ωs2+ω2
F(s)={cos(ωt)}=0estcos(ωt)dt= ss2+ω2
F(s)={tng(t)}=0esttng(t)dt= (1)ndnG(s)dsn forn= 1,2,...
F(s)={tsin(ωt)}=0esttsin(ωt)dt= 2ωs(s2+ω2)2
F(s)={tcos(ωt)}=0esttcos(ωt)dt= s2ω2(s2+ω2)2
F(s)={g(t)}=0estg(t)dt= 1aG(sa)
F(s)={eatg(t)}=0esteatg(t)dt=G(sa)
F(s)={eattn}=0esteattndt= n!(sa)n+1 forn= 1,2,...
F(s)={tet}=0esttetdt= 1(s+1)2
F(s)={1et/T}=0est(1et/T)dt= 1s(1+Ts)
F(s)={eatsin(ωt)}=0esteatsin(ωt)dt= ω(sa)2+ω2
F(s)={eatcos(ωt)}=0esteatcos(ωt)dt= sa(sa)2+ω2
F(s)={u(t)}=0estu(t)dt= 1s
F(s)={u(ta)}=0estu(ta)dt= eass
F(s)={u(ta)g(ta)}=0estu(ta)g(ta)dt=easG(s)
F(s)={g(t)}=0estg(t)dt=sG(s)g(0)
F(s)={g(t)}=0estg(t)dt=s2G(s)sg(0)g(0)
F(s)={g(n)(t)}=0estg(n)(t)dt=snG(s)sn1g(0)sn2g(0)...g(n1)(0)